Answer:
covalent bond is the answer
The molarity of a solution : 0.4 M
<h3>Further explanation</h3>
Given
0.2 moles of Potassium Oxide
500 ml of water = 0.5 L
Required
The molarity
Solution
Molarity is a way to express the concentration of the solution
Molarity shows the number of moles of solute in every 1 liter of solution or mmol in each ml of solution

Assume volume of solution = volume of water(addition of solution volume from volume Potassium Oxide is negligible
Input the value :
M = 0.2 : 0.5
M = 0.4
Answer:
Q = 3.59x10⁻⁸
Yes, precipitate is formed.
Explanation:
The reaction of Na₂S with Mn(CH₃COO)₂ is:
Na₂S(aq) + Mn(CH₃COO)₂(aq) ⇄ MnS(s) + 2 Na(CH₃COO)(aq).
The solubility product of the precipitate produced, MnS, is:
MnS(s) ⇄ Mn²⁺(aq) + S²⁻(aq)
And Ksp is:
Ksp = 1x10⁻¹¹= [Mn²⁺] [S²⁻]
Molar concentration of both ions is:
[Mn²⁺] = 0.015Lₓ (6.42x10⁻⁴mol / L) / (0.015 + 0.025)L = <em>2.41x10⁻⁴M</em>
[S²⁻] = 0.025Lₓ (2.39x10⁻⁴mol / L) / (0.015 + 0.025)L = <em>1.49</em>x10⁻⁴M
Reaction quotient under these concentrations is:
Q = [2.41x10⁻⁴M] [1.49x10⁻⁴M]
<em>Q = 3.59x10⁻⁸</em>
As Q > Ksp, <em>the equilibrium will shift to the left producing MnS(s) </em>the precipitate
When you assume that the gas is behaving ideally, the gas molecules are very far from each other that they do not have any intermolecular forces. If it behaves this way, you can assume the ideal gas equation:
PV = nRT, where
P is the pressure
V is the volume
n is the number of moles
R is a gas constant
T is the absolute temperature
When the process goes under constant pressure (and assuming same number of moles),
P/nR = T/V = constant, therefore,
T₁/V₁=T₂/V₂
If V₂ = V₁(1+0.8) = 1.8V₁, then,
T₂/T₁ = 1.8V₁/V₁
Cancelling V₁,
T₂/300=1.8
T₂ =540 K
If you do not assume ideal gas, you use the compressibility factor, z. The gas equation would now become
PV =znRT
However, we cannot solve this because we don't know the value of z₁ and z₂. There will be more unknowns than given so we won't be able to solve the problem. But definitely, the compressibility factor method is more accurate because it does not assume ideality.