Answer:
Part A
HCOOH(aq) + NaOH(aq) → HCOONa(aq) + H2O(l)
Part B
ClCH2CH2CO2H(aq) + NaOH(aq) ------> ClCH2CH2CO2Na(aq) + H2O(l)
Explanation:
The reaction between an alkanoic acid and a base is a neutralization reaction. The reaction occurs as follows;
RCOOH + NaOH ----> RCOONa + H2O
We have to note the fact that the net ionic reaction still remains;
H^+(aq) + OH^-(aq) ---> H2O(l)
In both cases, the reaction can occur and they actually do occur as written.
The chart is attached below and the options are as follow,
A Benzene
B Methanol
C Hexane
D Octane
Answer: Option-B (Methanol) is the correct answer.
Explanation: As we know that the substance given to student is soluble in water. Therefore, those substances which are soluble in water are
polar in nature because water is
polar in nature and
Like Dissolves Like.
Hence, in chart it can easily be seen that
Methanol is also polar in nature due to presence of -O-H (polar) bond. So, the substance will dissolve in it.
Answer: 4.05 mol O2, 15.36 mol H2O
Explanation:
I can answer each question individually if you post them individually.
2a. 3.24 mol NH3 * (5 mol O2 / 4 mol NH3) = 4.05 mol O2
2b. 12.8 mol O2 ( 6mol H2O/ 5 mol O2) = 15.36 mol H2O
Essentially what I did was dimensional analysis. Multiplying in a way that the units cancel out so the only thing remains is what each question asks for.
<span>a. a chemical combination of two or more different materials.
For example: </span>For example, air is a mixture of gases, containing N, O, Ar, CO2
Answer:
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