Given what we know, we can confirm that the type of van der Waals interactions that occur between molecules of O2, SCl2, and CH4 in liquids of these substances are the presence of <u>London dispersion forces</u>.
<h3>What are London dispersion forces?</h3>
- They are a force of attraction between atoms.
- They are generated by electrostatic attraction.
- These forces are common between atoms in close proximity and occur often when compounds have a symmetrical distribution of atoms.
- They are generated by the formation of temporary dipoles.
Therefore, given the symmetry of the atoms disposition in these compounds and the temporary dipoles generated by the atoms being in close proximity, we can confirm that the van der Waals forces present in each compound are London dispersion forces.
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Answer:
A
Explanation:
The formula used is
PV = P1 * V1
P = x
P1 = 4x
V1 = 1
V2 = ?
x * 1 = 4x * V2 Divide both sides by x
x/x = 4x /x * V2
1 = 4*V2 Divide by 4
1/4 = 4*V2/4
1/4 = V2
The answer is A
Answer:
pH of the buffer is 10.10
Explanation:
trimethylamine is a weak base that, in presence with its conjugate base, trimethylammonium ion, produce a buffer.
To determine the pH of the buffer we use H-H equation for weak bases:
pOH = pKb + log [Conjugate acid] / [Weak base]
<em>pKb is -log Kb = 4.20</em>
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pOH = 4.20 + log [N(CH₃)₃] / [NH(CH₃)₃]
Replacing the concentrations of the problem:
pOH = 4.20 + log [0.20M] / [0.40M]
pOH = 3.90
As pH = 14 -pOH
<h3>pH of the buffer is 10.10</h3>
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