Question

A hunter stood at about 60 m away from a tree. He used the bow to release the arrow in order to shoot a coconut held by a monkey in the tree. The coconut was at a height of 25 m from the ground. The hunter aimed directly at the coconut and the arrow left the bow at 45 m/s making an angle of 20 degree to the horizontal. At the moment the hunter released the arrow, the monkey dropped the coconut such that it falls vertically from rest. Neglect air resistance and the arrow's size. What is the time taken for the arrow to hit the coconut?​

Answer 1

Answer:

Time taken to reach the tree

they have given the maximum height which is 25m

therefore...

v=u+at (upward)

0 = 45sin(20)-9.81t

t = 1.56s