PLEASE HELP!!! This is due today and I've been stuck on it! Thanks in advance!!
1 answer:
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Answer:
S = {0,2,3,4}
P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001
Mean = 0.879
Standard Deviation = 1.033
Step-by-step explanation:
Let the number of people having same birth month be = x
The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)
The number of ways of distributing their birthdays = 12⁴
The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)
P(X = 0) =
P(X=0) = 0.573
P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)
P(X=2) =
P(X=2) = 0.401
P(X=3) =
P(x=3) = 0.025
P(X=4) =
P(X=4) = 0.001
Mean,
Standard deviation,
SD = 1.033
Answer:
C) At most one sample is mutated
Step-by-step explanation:
If there are 15 samples, it means that 15 is the total (100%) of samples. Then, if we know that there is a chance that 3% are mutated, then we calculate the 3% of 15:
This means that at most one sample is mutated, as this result is not zero (we discard answer A), and 0.45 is not more than half of the samples.