Answer:
Look below.
Step-by-step explanation:
Log3^4x
4xLog3 ------> To expand you would take the exponent and put infront of Log
This is the answer if its expanded. The question was sort of scarce so if this is wrong im sorry.
Answer:
You write the question wrong but it's okay
Step-by-step explanation:
it will be 30
i hope my answer help you
Answer:
Present Time
Let X= Eric's age (4/5)X= Seth's age
Question: What are their ages now?________________________________________________________________________
Past (21 years ago)
X-21 =Eric's age (4/5)X-21=Seth's age
2*[4/5(X-21]=Eric's age
Therefore, X-21= 2*[4/5(X)-21]=Eric's age Substitution
_______________________________________________________________________
X-21= 8/5 X - 42 Solve for "X" by adding 42 to both sides.
X-21+42=(8/5) X
X+21 = (8/5)X Subtract "X" from both sides.
21=(3/5)X Multiply both sides of equation by reciprocal of (3/5), which is 5/3
21*(5/3)= X Finish the problem to find value of "X," which is Eric's age.
Then find 4/5 (X)= Seth's age
The answer is 8 sorry if I am worng I just need points
