50%
The very left point on the box of a box plot is the first quartile, the very right. The very left and right points are the minimum and maximum and the middle line is the second quartile. Since quarters each equal 25%, two quartiles, the data between the first and third quartile, would equal 50%. This is also evident by looking at the graph itself in this problem.
1) Call x the sample mean = 3.56
2) Call s the sample standard deviation = 0.2
3) Given that the variable is normally distributed and the sample is large, you determine the interval of confidence from:
x +/- Z(0.5) s/√n
Wehre Z(0.5) is the value of the probabilities over 5% (90% of confidence mean to subtract 10%, which is 5% for each side (tails) of the normal distribuition) and is taken from tables.
Z(0.5) = 0.3085
Then the inteval is
x +/- 0.385 *s /√n = 3.56 +/- 0.385 * 0.2/√45
3.56 +/- 0.011 = ( 3.549, 3.571). This is the answer.
Answer:
b
Step-by-step explanation:
because i got it right
Here's are the steps to solving it.
3-a+5-2a=17
-3a=9
a=-3
Use the equation C = 3.14 times 2 times the radius
