Answer:
equation of the circle J with center K(-7,3) and radius 6 is=
x^2+y^2+14x-6y+22=0
Step by step explanation:
Equation of circle with given centre (h,k) and radius r is
(x-h)^2+(y-k)^2=r^2
Given centre are K(-7,3) and radius 6.
So equation of Circle=
(x- -7)^2+(y-3)^2=6^2
x^2+14x+49+y^2-6y+9=36
x^2+y^2+14x-6y+22=0 answer
Answer:
Hi! The correct answer is A. 80 Miles!
Step-by-step explanation:
The square root of 293 is 17.11.
Answer:
2h
Step-by-step explanation:
2h
I hope this answer is correct
