3 is the answer to your question
Question: The force between a pair of 0.005 C is 750 N. What is the distance between them?
Answer:
17.32 m
Explanation:
From coulomb's Law,
F = kqq'/r²........................... Equation 1
Where F = Force between the force, q' and q = both charges respectively, k = coulomb's constant, r = distance between both charges.
make r the subject of the equation above
r = √(kqq'/F)..................... Equation 2
From the question,
Given: q = q' = 0.005 C, F = 750 N
Constant: k = 9.0×10⁹ Nm²/C².
Substitute these values into equation 2
r = √(9.0×10⁹×0.005×0.005/750)
r = √(300)
r = 17.32 m.
Hence the distance between the pair of charges = 17.32 m
Answer:
Because the angle of the sun moves/rotates in the summer, the sun's rays move their angle and impact the earth.
Answer:
The magnitude of the force net is an acting object multiplied by acceleration of the object
Answer:
C would probably be the best answer.
Explanation:
Switches control the flow of an electrical current in a circuit. Switches open or close the circuit. If you open a circuit, you turn it off, and if you close it, you turn it on.
