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ira [324]
3 years ago
6

PLS HELP! WILL GIVE BRAINLIST!

Chemistry
1 answer:
Anestetic [448]3 years ago
8 0

Answer:

Energy retained at consumer level 1 -  units

Energy retained at consumer level 2 -  units

Energy retained at consumer level 3 -  units

Explanation:

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what electronic transition in a hydrogen atom starting from n=7 energy level will produce infrared radiation with energy of 55.1
Lostsunrise [7]

Answer:

(<em>n</em> = 7) ⟶ (<em>n</em> = 4)

Explanation:

1. Convert the energy to <em>joules per mole of electrons</em>.  

<em>E</em> = 55.1 × 1000 = 55 100 J/mol

2. Convert the energy to <em>joules per electron </em>

<em>E</em> = 55 100/(6.022 × 10²³)

<em>E</em> = 9.150 × 10⁻²⁰ J/electron

3. Use the Rydberg equation to <em>calculate the transition </em>

Rydberg's original formula was in terms of wavelengths, but we can rewrite it to have the units of energy. The formula then becomes  

\Delta E = R_{\text{H}} (\frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ n_{i}^{2}})

where  

R_{\text{H}} = the Rydberg constant = 2.178 × 10⁻¹⁸ J

n_{i} and n_{f} are the initial and final energy levels.

9.150 \times 10^{-20} = 2.178 \times 10^{-18}(\frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ 7^{2}})      

\frac{9.150 \times 10^{-20} }{2.178 \times 10^{-18}} = \frac{ 1}{ n_{f}^{2}} - \frac{ 1}{ 49}

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01} + \frac{1 }{49 }

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01 + 0.020 41}

\frac{ 1}{ n_{f}^{2}} = \text{0.042 01 + 0.020 41}

\frac{ 1}{ n_{f}^{2}} = \text{0.062 42}

n_{f}^{2} = \frac{1 }{ \text{0.062 42}}

n_{f}^{2} = 16.02

n_{f} = \sqrt{16.02}

n_{f} = 4.003 \approx 4

4 0
3 years ago
Find the density of a gas at STP if it’s molar mass is 112g/mol
AleksandrR [38]

Answer:

D= 5 g/L

Explanation:

M= D x Vm

M is the molar mass = 112g/mol

D is the density

Vm is the molar volume whuch is 22.4L at STP

now substitute;

112 = D x 22.4

D= 112\22.4

D= 5 g/L

5 0
3 years ago
Which of the following is the correct Lewis structure for methane (CHA)?
Mkey [24]

The correct lewis structure of methane(CH4)

C. H:C:H:H

6 0
3 years ago
Halocarbons contain carbon, hydrogen, and atoms from which set of elements?
Mnenie [13.5K]
Key word is “halo”, as in “halogens”. The halogens are group 7 on the periodic table, which includes Florine, Chlorine, Bromine, and Iodine

Answer is 4.
5 0
4 years ago
Atomic number of a member of halogens
ELEN [110]
Bromine 35

Chlorine 17

Flourine 9

Iodine 53

Astatine 85
4 0
3 years ago
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