1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aleksley [76]
3 years ago
8

What is the mass of the solution when 1 pound of salt is dissolved in 20 pounds of water?

Chemistry
1 answer:
kotykmax [81]3 years ago
5 0

Answer:

Explanation:

The dissolution of salt in water is basically a physical process and the law of conservation of mass which states that mass can neither be created nor destroyed applies. The mass of each component before dissolution will be same after dissolution.

When one pound of salt is dissolved in 20 pounds of water, the resulting solution will weigh 1+20 pounds.

mass of solution = mass of salt + mass of water

   = 1+20

mass of solution = 21 pounds

Have a nice day

You might be interested in
What is the total number of electron pairs shared between the carbon atom and one of the oxygen atoms in a carbon dioxide molecu
TEA [102]
The answer is 2 pairs. The carbon atom has 4 electrons and oxygen atom has 6 electrons. The purpose of shared electron is to get 8 electrons at the outer layer. So the carbon atom needs to share 4 electrons which is 2 pairs with oxygen to be stable.
7 0
3 years ago
If the volume and moles of a container are held constant, the temperature of a gas is inversely proportional to the pressure.
noname [10]

Answer:

FALSE

Explanation:

Assuming that the gas is ideal

Therefore the gas obeys the ideal gas equation

<h3>Ideal gas equation is </h3><h3>P × V = n × R × T</h3>

where

P is the pressure exerted by the gas

V is the volume occupied by the gas

n is the number of moles of the gas

R is the ideal gas constant

T is the temperature of the gas

Here volume of the gas will be the volume of the container

Given the volume of the container and number of moles of the gas are constant

As R will also be constant, the pressure of the gas will be directly proportional to the temperature of the gas

P ∝ T

∴ Pressure will be directly proportional to the temperature

4 0
3 years ago
Predict the major product(s) formed when hexanoyl chloride is treated with c6h5co2na.
postnew [5]
Following reactions show the major product,

3 0
3 years ago
STEP 7: LEAD
GenaCL600 [577]

Answer:

answer is 76

Explanation:

pls mark me brainliest right

4 0
3 years ago
If the density of a certain spherical atomic nucleus is 1.0 _ 1014 g cm_3 and its mass is 2.0 _ 10_23 g, what is its radius in c
melamori03 [73]
1) Calculate the volume from d = m/V => V = m/d = 2.0*10^-23 g /  1.0*10^14 g/cm^3 = 2.0*10^-9 cm^3

2) Now use the formula of volume for a sphere: V = (4/3)π(r^3) =>

r =∛[3V/(4π)] = ∛[(3*2.0*10^-9 cm^3) / (4π)] = 0.48*10^-3 cm = 4.8*10^-4 cm = 0.00048cm
5 0
3 years ago
Other questions:
  • Calculate the number of molecules in 0.75 moles of CH₄. x 10²³ molecules
    14·1 answer
  • Vitamin K is involved in normal blood clotting. When 2.09 g of vitamin K is dissolved in 25.0 g of camphor, the freezing point o
    9·1 answer
  • the variable in an expierment that is being observed and changes in response to an independent variable
    6·1 answer
  • What type of bond would two sulfur atoms require to form a molecule?
    9·2 answers
  • NO<br> Assign oxidation numbers to each element in this compound.
    9·1 answer
  • g The boiling of water is a Question 4 options: chemical and physical damage chemical change because a gas (steam) is given off
    8·1 answer
  • What is the name for BrCl4
    14·1 answer
  • Which term is used to describe the variety of inheritable traits in a species? (4 points)
    8·2 answers
  • Please answer correctly !!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!
    15·1 answer
  • What type of tree has thin, waxy needles that drop throughout the year and help to retain water?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!