Answer:
8.25 moles
Explanation:
Given parameters:
Number of moles of Al produced = 11 moles
Unknown:
Number of moles of oxygen produced = ?
Solution:
To solve this problem, we need to understand the problem.
The decomposition of an aluminium oxide must has produced oxygen and aluminium,
2Al₂O₃ → 4Al + 3O₂
now since the known is the oxygen gas; we can find the unknown aluminium:
3 mole of O₂ was produced with 4 mole of Al
x mole of O₂ will be produced with 11 moles of Al
x = 
= 8.25 moles
Lets make x equal the number times you use the 1/5 ratio alloy and y equal the number of times you use the 3/1 ratio alloy. You can make the equation (x+3y)-(5x+y)=0 and (x+3y)+(5x+y)=350
Then you can make the system of equation of:
-4x+2y=0 (this is y=2x)
6x+4y=350
You can make 6x+8x=350 by through substitution and solve of x.
14x=350
x=25 (which means y=50)
that means that the weight of the 1/5 ratio alloy is 150 pounds.
(25+(5x25))=150
the weight of the 3/1 ratio alloy is 200 pounds.
((50x3)+50)=200
I hope this helps.
The average atomic mass of tellurium, calculated from its eight isotopes (Te-120 (0.09%), Te-122 (2.46%), Te-123 (0.87%), Te-124 (4.61%), Te-125 (6.99%), Te-126 (18.71%), Te-128 (31.79%), and Te-130 (34.48%)) is 127.723 amu.
The average atomic mass of Te can be calculated as follows:
Where:
m: is the mass
%: is the abundance percent
Knowing all the masses and abundance values, we have:
To find the <u>average atomic mass</u> we need to change all the <u>percent values</u> to <u>decimal ones</u>
Therefore, the average atomic mass of tellurium is 127.723 amu.
You can find more about average atomic mass here brainly.com/question/11096711?referrer=searchResults
I hope it helps you!
In chemistry, the elements that exist with electrical charges are called ions. These ions can carry a positive charge, for which they are called cations, or a negative charge, for which they are called anions. These ions carry an electric charge because they do not conform to the stable number of electrons of their neutral atom. Because of this, they carry excess electrons for cations, and a lack of electrons for the anions.
When cations and anions form together such that there is a complete transfer of electrons so that each ion would be neutral, an ionic bond is formed. If you write the reaction, the superscripts and subscripts would just cross-multiply. If the cation is A⁺ᵃ, and the anion is B⁻ˣ, then the ionic compound would then be AₓBₐ. Of x=a, then they will cancel out which will yield AB. Therefore, the ionic compound for each pair of ions are:
NH₄⁺ + OH⁻ = NH₄OH
Mg²⁺ + CO₃²⁻ = MgCO₃
Fe³⁺ + PO₃⁴⁻ = Fe₄(PO₃)₃
