It would form a negative ion... it lacks 1 e in its valence shell., it is easier for F to accept an e than to shed all existing 7.
e= electron
Answer : The value of change in entropy for freezing process is, -18.07 J/mol.K
Explanation :
Formula used :
where,
= change in entropy
= change in enthalpy of fusion = 3.17 kJ/mol
As we know that:
= freezing point temperature = 
Now put all the given values in the above formula, we get:
Therefore, the value of change in entropy for freezing process is, -18.07 J/mol.K
Non-valence electrons: 1s22s22p6. Therefore, we write the electron configuration for Na: 1s22s22p63s1. What is the highest principal quantum number that you see in sodium's electron configuration? It's n = 3, so all electrons with n = 3 are valence electrons, and all electrons with n < 3 are non-valence electrons.
The answer is B: chronological order
What's your question? Am I missing something?
