Complete the following nuclear bombardment equation by filling in the nuclear symbol for the missing species.
1 answer:
Answer:
Strontium Sr
Explanation:
By the law of mass conversion the nuclear mass remains constant in a reaction which means initial mass and atoic number will be equal to final atomic number and atomic mass respectively.
²³⁵₉₂U + ¹₀n → ? + ¹³⁹₅₄Xe + 3 ¹₀n
Here atomic mass =
235 + 1 = A + 139+3 ( A -= atomic mass of ?)
A = 236 - 142
A = 94
And, atomic number would be =
92 = B + 54
B = 92 - 54
B = 38
So, the atomic number of ? will be 38 and atomic mass will be = 94
The element with 38 atomic number is = Strontium Sr
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-20.16 KJ of heat are released by the reaction of 25.0 g of Na2O2.
Explanation:
Given:
mass of Na2O2 = 25 grams
atomic mass of Na2O2 = 78 gram/mole
number of mole =
=
=0. 32 moles
The balanced equation for the reaction:
2 Na2O2(s) + 2 H2O(l) → 4 NaOH(aq) + O2(g) ∆Hο = −126 kJ
It can be seen that 126 KJ of energy is released when 2 moles of Na2O2 undergoes reaction.
similarly 0.3 moles of Na2O2 on reaction would give:
=
x =
= -20.16 KJ
Thus, - 20.16 KJ of energy will be released.