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vichka [17]
2 years ago
9

If a recycling center collects 3245 aluminum cans and there are 22 aluminum cans in 1 lb what volume in liters

Chemistry
1 answer:
Bad White [126]2 years ago
3 0

The volume in liters of 3245 aluminum cans is 24.8 L.

A recycling center collects 3245 aluminum cans and there are 22 aluminum cans in 1 lb. The mass of 3245 aluminum cans is:

3245 cans \times \frac{1lb}{22cans} = 147.5 lb

To convert mass to volume, we need the density of aluminum (5.95 lb/L). The volume corresponding to 147.5 lb of aluminum is:

147.5 lb \times \frac{1L}{5.95 lb} = 24.8 L

The volume in liters of 3245 aluminum cans is 24.8 L.

You  can learn more about density here: brainly.com/question/1841285

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(7.6 x 104m) x (1.5 x 107m)
cluponka [151]

Answer:

the answer should 126 859.2 m2

3 0
2 years ago
Read 2 more answers
Estimate the ph of the resulting solution prepared by mixing 1.0 mole of solid disodium phosphate (na2hpo4) and 1.25 mole of hyd
GenaCL600 [577]

The HCl added = 1.25 moles

and the moles of Na2HPO4 = 1 mole

Now when acid is added in the given solution of Na2HPO4

One mole of H+ will react with one mole of Na2HPO4 to given one mole of NaH2PO4

Na2HPO4  + H+  ---> NaH2PO4

Now this one mole formed NaH2PO4 will further react with 0.25 moles of H+ left to form 0.25 moles of  H3PO4 and 0.75 moles of NaH2PO4 will remain in the solution

So this will result into formation of a buffer of phosphoric acid and NaH2PO4

NaH2PO4  + H+  ---> H3PO4

pKa of H3PO4 = 2.1

so pH = pKa + log [salt] / [acid] = 2.1 + log [0.75 / 0.25] = 2.58

so the pH will be in between 2.1 to 7.2

7 0
3 years ago
Calculate each of the following quantities:<br> (a) Total number of ions in 38.1 g of SrF₂
adelina 88 [10]

The total number of ions in 38.1 g of SrF₂ is 5.479 x 10²³.

<h3>What are ions?</h3>

Ions are the elements with a charge on them. It happens when they share electrons with other atoms to form a compound.

We have to calculate the total number of ions in 38.1 g of .

The molar mass of SrF₂ = 125.62 g/mol

The number of moles = 38.1 g of  1.0 mol / 125.62  = 0.30329 moles

Given that, total moles of SrF₂ ions in  = 1.0 mol of + 2.0 moles of  = 3.0 moles

Total moles of ions in 0.30329 moles of

= (0.30329 moles of SrF₂) x 3.0 / 1.0  = 0.90988 mol ions

We know that,

1.0 mole of ions = 6.023 x 10²³ ions

Thus, the number of total ions = ( 0.90988 mol ions) x  6.023 x 10²³ / 1.0 mol = 5.479 x 10²³ ions

Thus, the number of ions is in 38.1 g of 5.479 x 10²³ ions

To learn more about ions, refer to the link:

brainly.com/question/14295820

#SPJ4

8 0
1 year ago
Which of the following group 7A elements is the most reactive ?
Scrat [10]
C) Fluorine is the most reactive among halogens
3 0
3 years ago
Read 2 more answers
How does maximum boiling azeotropic mixture is separated using fractional distillation?
Evgesh-ka [11]

Answer:

By heating the mixture to maximum boiling point and then the solution is distilled at a constant temperature without having a change in composition.

Explanation:

An azeotropic mixture is also called a constant boiling mixture and it is a mixture of two or more liquids whose proportions cannot be altered by simple distillation due to the fact that when an azeotropic mixture is boiled, the vapor has the same proportions of constituents as the unboiled mixture.

Now, maximum boiling azeotropic mixture are the solutions with negative deviations that have an intermediate composition  for which the vapor pressure of the solution is minimum and as a result, the boiling point is maximum. At that point, the solution will distill at a constant temperature without having a change in composition.

4 0
2 years ago
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