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2 years ago

The diagram below show an enlarged view of the beams of a triple-beam balance

Chemistry

1 answer:

VLD [36.1K]2 years ago

6 0

Answer:

1) 455.2 g. 2) 545.2 g.

Explanation:

i think this is right

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Food is the only limiting factor that keeps populations from growing too large true or false?

topjm [15]

FALSE

There are other limiting factors like lack of space, diseases, and com petition.

6 0

3 years ago

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Calculate the energy in joules and calories required to heat 50.0g silver from 106c to 255c.

Ganezh [65]

Answer:

Explanation:

use this fromula

q = m c ∆t

m is mass of silver =50 g

∆t is difference in temperature= 255-106=149

C= specific heat fo silver ( should be mentioned in your question )

5 0

2 years ago

Bromine reacts with nitric oxide to form nitrosyl bromide as shown in this reaction: br2(g) + 2 no(g) → 2 nobr(g) a possible mec

Svetach [21]

The overall reaction is given by:

$Br_{2}(g) + 2 NO(g) \rightarrow 2 NOBr(g)$

The fast step reaction is given as:

$NO(g) + Br_{2}(g) \rightleftharpoons NOBr_{2}(g) (fast; k_{eq}= \frac{k_{1}}{k_{-1}})$

The slow step reaction is given as:

$NOBr_{2}(g) + NO(g) \rightarrow 2 NOBr(g)$ (slow step $k_{2}$ )

Now, the expression for the rate of reaction of fast reaction is:

$r_{1}=k_{1}[NO][Br_{2}]-k_{-1}[NOBr_{2}]$

The expression for the rate of reaction of slow reaction is:

$r_{2}=k_{2}[NOBr_{2}] [NO]$

Slow step is the rate determining step. Thus, the overall rate of formation is the rate of formation of slow reaction as $[NOBr_{2}]$ takes place in this reaction.

The expression of rate of formation is:

$\frac{d(NOBr)}{dt}=r_{2}$

= $k_{2}[NOBr_{2}][NO]$ (1)

Now, consider that the fast step is always is in equilibrium. Therefore, $r_{1}=0$

$k_{1}[NO][Br_{2}]= k_{-1}[NOBr_{2}]$

$[NOBr_{2}] = \frac{k_{1}}{k_{-1}}[NO][Br_{2}]$

Substitute the value of $[NOBr_{2}]$ in equation (1), we get:

$\frac{d(NOBr)}{dt}=k_{2}[NOBr_{2}][NO]$

= $k_{2} \frac{k_{1}}{k_{-1}}[NO][Br_{2}][NO]$

= $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$

Thus, rate law of formation of $NOBr$ in terms of reactants is given by $\frac{k_{1}k_{2}}{k_{-1}}[NO]^{2}[Br_{2}]$ .

4 0

3 years ago

Calcula la cantidad de gramos que hay en 12,5 mol de NaCl (Masa Na: 23,0; Cl: 35,5).

Anon25 [30]

Answer:

731.25 g

Explanation:

The question asks us to calculate the mass of 12.5 moles of NaCl. The individual relative atomic masses of the elements were supplied. We must first obtain the molar mass of sodium chloride as follows;

Molar mass of sodium chloride= 23.0 + 35.5 = 58.5 gmol-1

From the formula;

Number of moles (n) = mass /molar mass

Number of moles of sodium chloride= 12.5 moles

Mass of sodium = The unknown

Molar mass of sodium chloride= 58.5gmol-1

Mass of sodium chloride= number of moles × molar mass

Mass of sodium chloride= 12.5 × 58.5

Mass of sodium chloride= 731.25 g

4 0

2 years ago

2. Which of the following is true about a carbonated soft drink?. . The carbon dioxide is the solvent, and water is the solute..

const2013 [10]

A carbonated soft drink hs a large amount of water dissolved with ample amount of carbon dioxide. In this case, the solvent is water and carbon dioxide is the solute. In 2, for the reaction <span>CH3COOH = CH3COO + H+, CH3COOH is a Bronsted-Lowry acid because it releases a proton which is H+. </span>

3 0

3 years ago

Read 2 more answers