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Feliz [49]
2 years ago
7

Help please

Mathematics
1 answer:
mezya [45]2 years ago
7 0

Answer:

Step-by-step explanation:

Remark

My guess is that what is confusing you is not what you have to do, but why it is disguised as g(n)

What you are doing in effect is setting up a table. You are also not certain where the table starts. And that is a problem. I will start it at zero, but it might be 1.

zero

n = 0

g(0) = 34 - 5*0

g(0) = 34

One

n = 1

g(1) = 34 - 5*1

g(1) = 34 - 5

g(1) = 29

Two

g(2) = 34 - 5*2

g(2) = 34 - 10

g(2) = 24

Three

g(3) = 34 - 5*3

g(3) = 34 - 15

g(3) = 19

Four

g(4) = 34 - 5*4

g(4) = 34 - 20

g(4) = 19

Answer

0      1       2       3      4

34  29     24     19     14

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Answer:

It depends on the value of x

Step-by-step explanation:

If x=1, then yes

Exponents come before multiplication, so even if 2*4=8, 2*4^2 is not equal to 8.

Ex:

2*4^2=32

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2 years ago
What is the equation of (0,2) and (3,0)
ivolga24 [154]
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8 0
3 years ago
Answer quickly please
olga nikolaevna [1]

Answer:

linear I think so ................

3 0
2 years ago
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Solve for x in the equation 4x-3(4x-5)=3
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7 0
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1.13 Thank you! (Sorry it’s so blurry)
VikaD [51]
\sqrt[8]{48^4}  can be rewritten as 48^4 to the \frac{1}{8}  power:

(48^4)^ \frac{1}{8}

Now, applying exponent rules (multiply exponent inside parentheses by the one outside parentheses), we get:

(48^ \frac{1}{2})

This is equivalent to \sqrt{48}, so now, we just simplify:

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So:

\sqrt[8]{48^4} =4 \sqrt{3} 


4 0
3 years ago
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