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pentagon [3]
2 years ago
6

What is the force required to move a block of mass 150 pound by a distance of 5ft in 8 seconds?

Physics
1 answer:
Nadusha1986 [10]2 years ago
8 0

Force required to move a block is 1.615 N

Given:

mass of block = m = 150 pounds = 68 kg

distance = d = 5 ft = 1.52 metres

time = t = 8 sec

To Find:

force required to move the block

Solution: Force is defined as product of mass and acceleration and it's unit is N or Newton.

Velocity = displacement/ time = 1.52 / 8 = 0.19 m/s

Acceleration = velocity/time = 0.19/8 =

0.023 m/s^2

Force = mass x acceleration = 68x0.023 = 1.615 N

Hence, force required to move the block is 1.615 N

Learn more about Force here:

brainly.com/question/12970081

#SPJ4

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Football helmets are made with padding that helps reduce head injuries when a player collides with an object. Which bestexplains
Vlad1618 [11]

football hemets have pads that are filled with air and thick foam so when they are hit the foam asorbs the hit and the air keeps the hard outer shell of the helmet from hiting the players head

3 0
3 years ago
Read 2 more answers
What force is necessary to accelerate a 2500 kg care from rest to 20 m/s over 10 seconds?
EleoNora [17]
Force = mass x acceleration
force = 2500kg x (20m/s / 10m/s)
force = 2500kg x 2m/s^2
force = 5000kg m/s^2 = 5kN

i hope this is right (^^)
4 0
3 years ago
In order to increase the amount of work done, we need to:
Nadusha1986 [10]
Option (D) is the correct one.


In order to increase the amount of work done, we need to increase the force applied to the object.
8 0
3 years ago
A Bullet Off mass 100 gm is fired From A Gun Off mass 5 Kg. If the backward velocity of the gun's 5 m / s, what is forward veloc
Elena L [17]

Answer:

250 m/s

Explanation:

The mass of the bullet, m₁ = 100 g = 0.1 kg

The mass of the gun, m₂ = 5 kg

The backward velocity of the gun, v₂ = -5 m/s

Given that the momentum is conserved, we have;

The total initial momentum = The total final momentum

The gun and the bullet are at rest, therefore, we have;

The initial momentum = 0

The total final momentum = m₁·v₁ + m₂·v₂

Where;

v₁ = The forward velocity of the bullet

Therefore, we get;

m₁·v₁ + m₂·v₂ = 0

0.1 kg × v₁ + 5 kg × (-5 m/s) = 0

0.1 kg × v₁ = 5 kg × 5 m/s

v₁ = (5 kg × 5 m/s)/(0.1 kg) = 250 m/s

The forward velocity of the bullet, v₁ = 250 m/s

6 0
3 years ago
The direction of deflection of an electron beam in a magnetic field can be determined by which of the following?
amid [387]

Answer:

Right Hand Rule

Explanation:

When a charged particle travels in a magnetic field, it experiences a force whose magnitude is given by:

F=qvBsin\theta

where

q is the charge of the particle

v is the velocity

B is the magnetic field strength

\theta is the angle between the directions of v and B

The direction of the force can be determined by using the Right Hand Rule, as follows:

- index finger: this should be put in the direction of the velocity

- middle finger: this should be put in the direction of the magnetic field

- thumb: this will give the direction of the force -> however, for a negative charge (as the electron) the direction must be reversed, so it will be opposite.

4 0
3 years ago
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