Question

A water-walking ball has a volume of approximately 904.32 cubic feet. What is the radius of the ball? (V = 4/3(pi)r^3)

Answer 1

Answer:

The radius of the ball is of 6 feet.

Step-by-step explanation:

The radius of the ball in spheric format is given by:

$V = \frac{4\pi r^3}{3}$

In which r is the radius.

A water-walking ball has a volume of approximately 904.32 cubic feet. What is the radius of the ball?

Volume in cubic feet, so the radius will be in feet. We have to find r for which $V = 904.32$. So

$V = \frac{4\pi r^3}{3}$

$904.32 = \frac{4\pi r^3}{3}$

$r^3 = \frac{904.32*3}{4\pi}$

$r = \sqrt[3]{\frac{904.32*3}{4\pi}}$

$r = 6$

The radius of the ball is of 6 feet.