Please help, I don’t know how to solve this problem :( it’s
2 answers:
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Answer:
46.67% probability that they flew with airline B.
Step-by-step explanation:
We have these following probabilities:
A 40% probability that a traveler chooses airline A.
A 35% probability that a traveled chooses airline B.
A 25% probability that a traveler chooses airline C.
If a passenger chooses airline A, a 10% probability that he arrives late.
If a passenger chooses airline B, a 15% probability that he arrives late.
If a passenger chooses airline C, a 8% probability that he arrives late.
If a randomly selected traveler is on a flight from Seattle which arrives late to Sydney, what is the probability that they flew with airline B?
This can be formulated as the following problem:
What is the probability of B happening, knowing that A has happened.
It can be calculated by the following formula
Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.
So
What is the probability that the traveler flew with airline B, given that he was late?
P(B) is the probability that he flew with airline B.
So
P(A/B) is the probability of being late when traveling with airline B. So P(A/B) = 0.15.
P(A) is the probability of being late. This is the sum of 10% of 40%(airline A), 15% of 35%(airline B) and 8% of 25%(airline C).
So
Probability
46.67% probability that they flew with airline B.
Answer:
$4,499.46
Step-by-step explanation:
We can use the compound interest formula for this problem:
P = initial balance
r = interest rate (decimal)
n = number of times compounded annually
t = time
First, lets change 4% into a decimal:
4% -> -> 0.04
Now lets plug the values into the equation as shown below:
Don will have $4,499.46 at the end of the three years.
Answer:
1. ridescost+admission=total
if x=number of tickets and y is total and cost per ride is 1.25 then
1.25x+admission=y
if we solve
when x=25, y=43.75
1.25(25)+admission=43.75
31.25+admission=43.75
minus 31.25 from both sides
admission=12.50
a.
y=1.25x+12.5
b.
x is number of tickets and y is total cost
c. math, seriously, just read what is above option a (the one in the top of the answer)
if you're too lazy then:
ridescost+admission=total
if x=number of tickets and y is total and cost per ride is 1.25 then
1.25x+admission=y
if we solve
when x=25, y=43.75
2.
(a)
m = (y2 - y1) / (x2 - x1) = (4 - 9)/(-2 - 8) = -5/(-10) = 1/2
(b)
y - y1 = m(x - x1)
Using the first given point,
y - 9 = (1/2)(x - 8)
Using the second given point,
y - 4 = (1/2)(x + 2)
note they both simplify to
y = (1/2)x + 5
(c)
y = (1/2)x + 5
3.
