Answer:
D.f(x)=2x-9and g(x)=X+9/2
Answer:
2x + 3y + 5z = 9
Step-by-step explanation:
The normal defines all the planes perpendicular to that vector. To isolate to a single plane, just apply the known point.
ax + by + cz = d
2x + 3y + 5z = d
2(1) + 3(-1) + 5(2) = 9
Let
x--------> the unknown scale size
we know that
N 1---------> x
N 2---------> 1
N 3---------> 0.937
N 4--------->0.878
scale factor=0.937/0.878------> 1.0672
to obtain the size N 3 ----> multiply the size N 4 by 1.0672
size N 3=1.0672*0.878-----> 0.937
so
to obtain the size N 2 ----> multiply the size N 3 by 1.0672
size N 2=1.0672*0.937------> 1
to obtain the size N 1 ----> multiply the size N 2 by 1.0672
size N =1.0672*1------> 1.0672
hence
x=1.0672-------> x=1.067
the answer is the unknown scale size is 1.067
The answer is 10/3. Because you have 3 wholes and 1/3 so, 3x3 is 9 and you still have the extra 1 so 9+1=10 therefore your answer would be 10/3
