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prohojiy [21]
3 years ago
12

Tina walked 300m in 100s and200m in 150s. What was her average speed.

Physics
1 answer:
skelet666 [1.2K]3 years ago
5 0

Answer:

2m/s

Explanation:

Total Distance = 300m+200m = 500m

Total Time = 100s+150s = 250s

Average Speed = Total distance travelled/Total time taken

=500m/250s

=2m/s

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Although 0 dB is often referred to as the lower threshold of human hearing, it is important to realize that the human ear is not
d1i1m1o1n [39]

Answer:

a) 3000 Hz;

b) 30 dB;

c) 1000 times.

Explanation:

a) From the human audiogram given on the figure below the black line represents the threshold for hearing the sound at each frequency. We see that the least intensity is necessary for the frequency of about 3000 Hz.

b) Using the same audiogram we see that we would need the sound of the intensity of about 30dB.

c) The least perceptible sound at 1000 Hz must be 0dB while at 100 Hz it is 30dB. These are logarithmic quantities. To transform them to the linear quantities we use the formula

I(\text{in dB})=10\log\frac{I}{I_0(\text{at }1000\text{ Hz})},

where  I_0(\text{at }1000\text{ Hz}) is the hearing threshold at 1000 Hz.

Therefore we have the following

0\text{ dB}=10\log\frac{I_1}{I_0(\text{at }1000\text{ Hz})}\quad 30\text{ dB}=10\log\frac{I_2}{I_0(\text{at }1000\text{ Hz})}

I_1 is the threshold at 1000Hz and I_2 is the threshold at 100Hz.

By exponentiating we have

10^0=\frac{I_1}{I_0(\text{at }1000\text{ Hz})},\quad 10^3=\frac{I_2}{I_0\text{at }1000\text{ Hz}}.

Now dividing these two equations we get

\frac{I_2}{I_1}=\frac{10^3}{10^0}=1000.

Therefore, the least perceptible sound at 100Hz is 1000 times more intense than the least perceptible sound at 1000Hz.

Note: I got these values unisng the audiogram that is attached here. The one that you have might be slightly different and might yield different answers.

7 0
3 years ago
5 Ohm 3 Ohm 2 Ohm R=?​
Tema [17]

Answer:

6.2 ohm

Explanation:

Let R1 = 5 ohm

R2= 3 ohm

R3= 2 ohm

Since R3 and R2 are parallel then net resistance R' is given by

1/R' = 1/R2 + 1/R3

1/R' = 1/3 + 1/2

1/R' = 5/6

then

R' = 6/5 = 1.2 ohm

Now R1 and R' are in series, so

R = R1 + R'

R = 5 + 1.2

R = 6.2 ohm

5 0
3 years ago
An apple in a tree has a gravitational potential energy of 17.5 J and a mass of 0.36 kg. About how high from the
marissa [1.9K]

Answer:

Answer: The height of the apple from the ground is at 49552.61071 m or is approximately at 5.0 × 10 m.

4 0
3 years ago
On a cold winter's day heat leaks slowly out of a house at the rate of 20.5 kw. if the inside temperature is 22° c, and the outs
Lina20 [59]
From Clausius theorem we get the formula for the change of entropy:
dS=\frac{dQ}{T}
dS is the change of entropy, dQ is the change of energy, and T is the temperature in Kelvin.
We need to convert those temperatures:
T_{in}=22^\circ C= 273.15+22=295.15K\\ T_{out}=-17.5^\circ C=273.15-17.5=255.65K
Entropy changes inside and outside:
$$Inside$: dS= \frac{-dQ}{T_in}=\frac{-20\cdot 10^3}{295.15K}=-67.76\frac{J}{K}
$$Outside$: dS= \frac{+dQ}{T_out}=\frac{+20\cdot 10^3}{255.65K}=+78.23\frac{J}{K}
The net entropy increase is:
dS=+78.23\frac{J}{K}-67.76\frac{J}{K}=+10.47\frac{J}{K}
6 0
4 years ago
The heart rate that indicates your fitness level is the
MrRa [10]

The heart rate that indicates your fitness level is the Resting Heart Rate.

<u>Explanation:</u>

The statement from Welch says that when we practise more and do an exercise harder, then the heart rate at rest would be low. This is the main reason for considering resting heart rates as a good indicator to one’s fitness level. The normal adult heart rate at rest is 60 to 100 bpm (beat per minute).

In general, a lower heart rate means a calmer heart rate and good heart health. For example, for a well-trained athlete, a normal heart rate can be closer to 40 bpm. Our resting rhythm, the measure of how often the heart beats every minute at rest.

8 0
3 years ago
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