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Vadim26 [7]
2 years ago
12

Where is the frequency of ultrasound in relation to the range of human ability to hear

Physics
2 answers:
Arte-miy333 [17]2 years ago
8 0

The frequency of "ultra"sound is <em>much much much higher</em> than any frequency that any human being can hear.

Ultrasound frequencies in diagnostic radiology range from 2 MHz to approximately 15 MHz (although even higher frequencies may be used in some situations) !  That's a range from <em>100 times</em> to <em>750 times</em> the average limit of human hearing (20,000 Hz) !  (See more numbers below.)

Even when ultrasound blasts through your canal, shakes your tympanum, oscillates your ossicles, and attacks your hair cells, your brain never has a clue.

= = = = = = = = = = = = = = =

Looking at it another way:

-- The exact upper and lower limits of human hearing are different for just about every individual on Earth.  As a broad average for the whole human race, we commonly consider the range to be from 20 Hz to 20,000 Hz .

That's a range of almost exactly <u><em>10 octaves</em></u>.

-- Ultrasound operating at 2 MHz is <u><em>another 6.6 octaves</em></u> above the upper audible frequency limit.

--  Ultrasound operating at 15 MHz is <u><em>another 9.5 octaves</em></u> above the upper audible frequency limit.  

kykrilka [37]2 years ago
4 0

Answer:

ultra sounds have frequency higher than the upper audible limit of human hearing, for healthy, young adults.

Explanation:

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Complete Question

A wave is described by y(x,t) = 0.1 sin(3x + 10t), where x is in meters, y is in centimetres and t is in seconds. The angular wave  frequency is

Answer:

The  value is w =  10 \ rad /s

Explanation:

From the question we are told that  

    The equation describing the wave is y(x,t) = 0.1 sin(3x + 10t)

Generally the sinusoidal equation representing the motion of a wave is mathematically represented as

         y(x,t) =  Asin(kx + wt )

Where  w  is the  angular frequency

Now comparing this equation  with that given we see that

       w =  10 \ rad /s

 

               

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Danny lowers the sails on his boat. He paddles upstream at 19 km/hr. The current is still running downstream at 15 km/hr. What i
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Answer:

4 km/hr

Explanation:

The computation of the actual velocity is shown below:

Because the path of its paddles is opposed to the current direction, the real velocity can be determined by deducting the current velocity to its velocity while paddling

So, the actual velocity is

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