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3 years ago

Where is the frequency of ultrasound in relation to the range of human ability to hear

Physics

2 answers:

Arte-miy333 [17]3 years ago

8 0

The frequency of "ultra"sound is much much much higher than any frequency that any human being can hear.

Ultrasound frequencies in diagnostic radiology range from 2 MHz to approximately 15 MHz (although even higher frequencies may be used in some situations) ! That's a range from 100 times to 750 times the average limit of human hearing (20,000 Hz) ! (See more numbers below.)

Even when ultrasound blasts through your canal, shakes your tympanum, oscillates your ossicles, and attacks your hair cells, your brain never has a clue.

= = = = = = = = = = = = = = =

Looking at it another way:

-- The exact upper and lower limits of human hearing are different for just about every individual on Earth. As a broad average for the whole human race, we commonly consider the range to be from 20 Hz to 20,000 Hz .

That's a range of almost exactly 10 octaves.

-- Ultrasound operating at 2 MHz is another 6.6 octaves above the upper audible frequency limit.

-- Ultrasound operating at 15 MHz is another 9.5 octaves above the upper audible frequency limit.

kykrilka [37]3 years ago

4 0

Answer:

ultra sounds have frequency higher than the upper audible limit of human hearing, for healthy, young adults.

Explanation:

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astraxan [27]

Answer:

A) & B)

Explanation:

First, the numbers 12 and 13 represent the atomic mass number of the atoms.

So, A) is true: thus Carbon12 and Carbon 13 have different mass numbers.

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The amount of neutrons can be calculated by: mass number minus number of protons.

For Carbon 12: $12-6=6$

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B) is true, we just proved they have different amounts of neutrons.

In order for the charge of the atom to be neutral, the amount of electrons must be equal to the number of protons (as they have opposite charges). And we now know that the number of protons in Carbon12 and Carbon13 are always the same

C) is false, the number of electrons is the same in both atoms

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3 years ago

To practice Problem-Solving Strategy 16.1 Standing waves. An air-filled pipe is found to have successive harmonics at 800 HzHz ,

bazaltina [42]

Answer:

Length of the pipe = 53.125 cm

Explanation:

given data

harmonic frequency f1 = 800 Hz

harmonic frequency f2 = 1120 Hz

harmonic frequency f3 = 1440 Hz

solution

first we get here fundamental frequency that is express as

2F = f2 - f1 ...............1

put here value

2F = 1120 - 800

F = 160 Hz

and

Wavelength is express as

Wavelength = Speed ÷ Fundamental frequency ................2

here speed of waves in air = 340 m/s

so put here value

Wavelength =340 ÷ 160

Wavelength = 2.125 m

Length of the pipe will be

Length of the pipe = 0.25 × wavelength ......................3

put here value

Length of the pipe = 0.25 × 2.125

Length of the pipe = 0.53125 m

Length of the pipe = 53.125 cm

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3 years ago

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Bezzdna [24]

The magnification is 31.16.

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u = -19.3

f = -18.7 cm.

m = f/f-u

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Learn more about magnification here:-brainly.com/question/15744335

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1 year ago