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Julli [10]
3 years ago
12

Since silver and gold are both shiny, rare and do not corrode, they are ideal materials for making... what?

Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
4 0

Answer:

Jewelry

Explanation:

Gold and silver  are metals which are malleable, ductile, and lustrous. Also they are noble metals. since they are noble metals they are not affected by acid, oxygen, atmosphere and etc. hence gold and silver are used or suitable for making jewlery.

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gayaneshka [121]

Answer:

The answer is 10 degrees celsius

Explanation:

4 0
3 years ago
How many covalent bonds are generally formed by atoms with five valence electrons?
torisob [31]
Five five five five five
5 0
3 years ago
Read 2 more answers
The burning characteristics of a gasoline can be improved by converting the octane it contains into isooctane. This conversion r
bogdanovich [222]

Gasoline is refined petroleum used in engines as a fuel. It contains octane that can be converted to isooctane by adding catalysts like platinum and palladium.

<h3>What are catalysts?</h3>

Catalysts are substances that raise the reaction rate by decreasing the activation energy but do not get consumed themselves in a reaction.

Platinum and palladium metals can be used as a catalyst to convert the octane of the gasoline into isooctane as they are oxidation catalyst that converts the fuel components into water and carbon dioxide.

Therefore, platinum and palladium are used as catalysts in converting octane.

Learn more about catalysts here:

brainly.com/question/1392595

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7 0
1 year ago
Problem PageQuestion A chemist makes of magnesium fluoride working solution by adding distilled water to of a stock solution of
igomit [66]

Answer:

5.37 × 10⁻⁴ mol/L

Explanation:

<em>A chemist makes 660. mL of magnesium fluoride working solution by adding distilled water to 230. mL of a 0.00154 mol/L stock solution of magnesium fluoride in water. Calculate the concentration of the chemist's working solution. Round your answer to 3 significant digits.</em>

Step 1: Given data

  • Initial concentration (C₁): 0.00154 mol/L
  • Initial volume (V₁): 230. mL
  • Final concentration (C₂): ?
  • Final volume (V₂): 660. mL

Step 2: Calculate the concentration of the final solution

We want to prepare a dilute solution from a concentrated one. We can calculate the concentration of the final solution using the dilution rule.

C₁ × V₁ = C₂ × V₂

C₂ = C₁ × V₁ / V₂

C₂ = 0.00154 mol/L × 230. mL / 660. mL = 5.37 × 10⁻⁴ mol/L

5 0
3 years ago
Part A
KonstantinChe [14]

Answer:

The answer to your question is below

Explanation:

A.

[H₃O⁺] = 2 x 10⁻¹⁴ M

pH = ?

Formula

                                    pH = - log [H₃O⁺]

Substitution

                                    pH = - log [2 x 10⁻¹⁴]

Result

                                    pH = 13.7          

B.

[H₃O⁺] = ?

pH = 3.12

Formula

                                   pH = - log [H₃O⁺]

Substitution

                                   3.12 = - log [H₃O⁺]

                                   10^{-3.12} = [H_{3} O^{+}]

Result

                                  [H₃O⁺] = 7.59 M

   

7 0
3 years ago
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