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2 years ago

I just need help with this question please

Mathematics

2 answers:

gregori [183]2 years ago

8 0

Answer:

$71.29

Step-by-step explanation:

$60 x 1.09 = $65.40 (year one)

$65.40 x 1.09 = $71.286 (year two)

Vsevolod [243]2 years ago

6 0

Answer:

71.286

Step-by-step explanation:

60 x .09 = 65.4

65.4 x .09 = 71.286

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A drainage pipe 66 in. tall measures 25.12 in. around.

Schach [20]

In order to solve this using V= B(h) (The B is area of the base) you need a radius it doesn't give us that but it does give us the circumference.
C= 3.14(2r)
25.12=2r divide each by 2
12.56=r
now use this in the volume formula:
V= 12.56^2(3.14)(66)
V=32,692.86 cubic inches

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3 years ago

Evaluation. I need help on this

Lelechka [254]

For every negative power you divide by 10

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2 years ago

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Noelle is drawing fraction bars to model the sum of One-fifth and Three-fourths. What is the smallest number of equally sized pi

krek1111 [17]

Answer:

Step-by-step explanation:

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2 years ago

( 2 x -6 ) +4 ( x - 3 )

OLga [1]

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2 years ago

An NFL coach sometimes uses a defense that utilizes 3 defensive linemen, 4 linebackers, and 4 defensive backs. His roster (the p

Alexandra [31]

Answer:

68,600

Step-by-step explanation:

The order of the players is not important. For example, a defensive line of Shaq Lawson, Ed Oliver and Jerry Hughes is the same as a defensive line of Ed Oliver, Shaq Lawson and Jerry Hughes. So we use the combinations formula to solve this question.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

Defensive Lineman:

3 from a set of 8. So

$C_{8,3} = \frac{8!}{3!5!} = 56$

56 combinations of defensive lineman

Linebackers:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of linebackers

Defensive backs:

4 from a set of 7. So

$C_{7,4} = \frac{7!}{4!3!} = 35$

35 combinations of defensive backs

How many different ways can the coach pick the 11 players to implement this particular defense?

56*35*35 = 68,600

68,600 different ways can the coach pick the 11 players to implement this particular defense

7 0

3 years ago