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Contact [7]
3 years ago
10

What does the outer part of the disk turn into?

Physics
1 answer:
My name is Ann [436]3 years ago
8 0

Answer:

what does the outer part of the disk turn into

Explanation:

4) it gets sucked into the star

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A distressed car is rolling backward, downhill at 3.0 m/s when its driver finally manages to
konstantin123 [22]

Answer:

Explanation:

Acceleration is equal to the change in velocity over the change in time, or

a=\frac{v_f-v_i}{t} where the change in velocity is final velocity minus initial velocity. Filling in:

3.0=\frac{v_f-(-3.0)}{6.0} Note that I made the backward velocity negative so the forward velocity in our answer will be positive.

Simplifying that gives us:

3.0=\frac{v_f+3.0}{6.0} and then isolating the final velocity, our unknown:

3.0(6.0) = v + 3.0 and

3.0(6.0) - 3.0 = v and

18 - 3.0 = v so

15 m/s = v and because this answer is positive, that means that the car is no longer rolling backwards (which was negative) but is now moving forward.

5 0
3 years ago
A car with an initial velocity of 5.0 is acelerated at 3.0for 4.0seconds what os the velocity of tje car ofter the 4.0seconds
sasho [114]
Vf =Vi+at
Vf= 5 + 3*4
Vf=5+12
Vf=17m/sec
6 0
3 years ago
A constant net force of 20 N is applied to a 32kg car, causing it to speed up from 4.0 to 9.0 m/s. How long is the force applied
pishuonlain [190]

Answer:

8 seconds

Explanation:

From Newton's second law;

Ft = m(v-u)

F = Force applied

t = time taken

v = final velocity

u  = initial velocity

20 * t = 32 (9 - 4)

20t = 32 * 5

t = 32 * 5/ 20

t = 8 seconds

8 0
3 years ago
A particle with mass 1.81*10^-3kg and a charge of 1.22*10^-8C has, at a given instant, a velocity v= (3.0*10^4 m/s)j.
charle [14.2K]

Answer:

a = -0.33 m/s² k^

Direction: negative

Explanation:

From Newton's law of motion, we know that;

F = ma

Now, from magnetic fields, we know that;. F = qVB

Thus;

ma = qVB

Where;

m is mass

a is acceleration

q is charge

V is velocity

B is magnetic field

We are given;

m = 1.81 × 10^(−3) kg

q = 1.22 × 10 ^(−8) C

V = (3.00 × 10⁴ m/s) ȷ^.

B = (1.63T) ı^ + (0.980T) ȷ^

Thus, since we are looking for acceleration, from, ma = qVB; let's make a the subject;

a = qVB/m

a = [(1.22 × 10 ^(−8)) × (3.00 × 10⁴)ȷ^ × ((1.63T) ı^ + (0.980T) ȷ^)]/(1.81 × 10^(−3))

From vector multiplication, ȷ^ × ȷ^ = 0 and ȷ^ × i^ = -k^

Thus;

a = -0.33 m/s² k^

7 0
3 years ago
Difference between rest and motion​
creativ13 [48]
Rest - it is the state in which body doesn’t move from it’s place

motion - it is the state in which body moves from it’s place
3 0
3 years ago
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