Answer:
4v/3
Explanation:
Assume elastic collision by the law of momentum conservation:
where v is the original speed of car 1, v1 is the final speed of car 1 and v2 is final speed of car 2. m1 and m2 are masses of car 1 and car 2, respectively
Substitute 
Divide both side by 
, then multiply by 6 we have
So the final speed of the second car is 4/3 of the first car original speed
3, protons are positive and there are 3 positive atoms visible
Answer:3764.282 KPa
Explanation:
Given gusher shoots oil at h=25 m
i.e. the velocity of jet is
v=\sqrt{2gh}[/tex]
v=22.147 m/s
Now the pressure loss in pipe is given by hagen poiseuille equation
For 25 m head in terms of Pressure
Total Pressure=
=3543.557+220.725=3764.282 KPa
Answer:
37.7m/s: principle of conservation of momentum
Explanation:
The principle to make use of is the principle of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of momentum of bodies after collision. This bodies will move with the same velocity after collision.
Momentum = Mass × velocity
For car of mass 2200kg moving with velocity 33m/s:
Momentum of car before collision = 2200×33
= 72,600kgm/s
For the truck of mass 4500kg;
Momentum = 4500 ×(22-(-18)
= 4500×40
= 180000kgm/s
After collision, their momentum is:
Momentum after collision = (2200+4500)v
= 6700v
Using the principle above to get the common velocity v we have
72600+180000 = 6700v
252600 = 6700v
v = 252600/6700
v = 37.7m/s
