Question

Q|C Spherical waves of wavelength 45.0 cm propagate outward from a point source. (c) Explain how the phase of the wave at a distance of 240 cm compares with the phase at 60.0cm at the same moment.

Answer 1

We are given distance of the center of the source for two waves:

$D_{1} =240 cm$

$D_{2} =60 cm$

C) Calculating how their phases compares:

ΔФ240$=\frac{D_{2} }{D_{1} } .$ΔФ60

$\frac{240}{60} .$ΔФ60 = 4.ΔФ60

How can you determine a wave's phase?

• The period, or length of each cycle, is determined by dividing the frequency by 1, so 1/100 corresponds to a period of 0.01 seconds. The phase shift equation is given by ps = 360 * td / p, where td is the time interval between waves, p is the wave period, and ps is the phase shift in degrees.

Phase: The "Phase" of a waveform refers to the location of the moving particle and is expressed in "Radians or degrees."

Phase difference, also known as "Phase angle," is the amount of time that one wave precedes or follows another.

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