First off, Newton's second law<span> of motion is the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
So therefore, it would be a force is being applied to the mass</span>
Assuming the woman starts at rest, she descends the slide with acceleration <em>a</em> such that
(20.3 m/s)² = 2 <em>a</em> (42.6 m) → <em>a</em> ≈ 4.84 m/s²
which points parallel to the slide.
The only forces acting on her, parallel to the slide, are
• the parallel component of her weight, <em>w</em> (//)
• friction, <em>f</em>, opposing her descent and pointing up the slide
Take the downward sliding direction to be positive. By Newton's second law, the net force in the parallel direction acting on the woman is
∑ <em>F</em> (//) = <em>w </em>(//) - <em>f</em> = <em>ma</em>
where <em>m</em> = 77.0 kg is the woman's mass.
Solve for <em>f</em> :
<em>mg</em> sin(42.3°) - <em>f</em> = <em>ma</em>
<em>f</em> = <em>m</em> (<em>g</em> sin(42.3°) - <em>a</em>)
<em>f</em> = (77.0 kg) ((9.80 m/s²) sin(42.3°) - 4.84 m/s²) ≈ 135 N
Compute the work <em>W</em> done by friction: multiply the magnitude of the friction by the length of the slide.
<em>W</em> = (135 N) (42.6 m) ≈ 5770 N•m = 5770 J
Because the action and the reaction forces act on different objects
Explanation:
Newton's third law of motion states that:
<em>"When an object A exerts a force on an object B (action), then object B exerts an equal and opposite force (reaction) on object A"</em>
From the statement above, we clearly see that the two forces mentioned in the law act on different objects. In fact, the action is exerted on object B, while the reaction is exerted on object A.
When we are considering the free-body diagram of an object, we just represent all the forces acting on that object, but not the forces exerted on other objects: this means that the action and the reaction never appear in the same free-body diagram of the same object, so they do not cancel out, simply because they are applied to different objects.
Learn more about Newton's third law:
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Answer:
F1= 588 N
F2= 784 N
Explanation:
Please see the attached file.
Answer:
Explanation:
Formula to calculate the distance between two points 
and 
is,
d = 
Therefore, length of CD having coordinates C(3,1) and D(3, 3),
CD = 
= 2 units
Formula to find the midpoint of CD is,
M = 
= 
= (3, 2)
Therefore, length of CD = 2 units and (3, 2) are the coordinates of the midpoint of CD.
