This assumption is not valid because, there are some elements which exist in two or more forms; they have the same atomic number but differ in their mass number, which meas that they possess different number of neutrons. These type of element are called isotopes. Isotope have the same atomic number and similar physical and chemical properties but they have different number of neutrons and therefore possess different masses.
the percentage composition of carbon is 30.77%
Answer:
The products are CO₂ and H₂O.
The ballanced equation is this:
2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O
Explanation:
In any chemical reaction, where you see that you have a compound reacting only with oxygen (O₂), you are in front of combustion.
Products in combustion are always water vapor and carbon dioxide.
Take a look to the methane combustion.
CH₄ + 2O₂ → CO₂ + 2H₂O
1 mol of methane reacts with 2 moles of oxygen to form 1 mol of CO₂ and 2 moles of water.
This is the combustion for an alkene where 2 moles of the alkene reacts with 11 moles of oxygen to make water and CO₂ like this:
2C₄H₆ + 11O₂ → 8CO₂ + 6H₂O
Hey there!
Na + FeBr₂ → NaBr + Fe
Firstly, balance Br.
Two on the left, one on the right. Add a coefficient of 2 in front of NaBr.
Na + FeBr₂ → 2NaBr + Fe
Next, balance Na.
One on the left, two on the right. Add a coefficient of 2 in front of Na.
2Na + FeBr₂ → 2NaBr + Fe
Lastly, balance Fe.
One on the left, one on the right. Already balanced.
Our final balanced equation:
2Na + FeBr₂ → 2NaBr + Fe
Hope this helps!
Answer:
2–methylpropene.
Explanation:
To successfully name the compound given in the question, we must observe the following:
1. Determine the functional group of the compound.
2. Locate the longest continuous carbon chain. This gives the parent name of the compound.
3. Identify the substituent group attached and locate it's position by giving it the lowest possible count.
4. Combine the above to obtain the name of the compound.
Now, let us determine the name of the compound. This is illustrated below:
1. The functional group of the compound is the double bond i.e the compound is an alkene.
2. The longest continuous carbon chain is 3 i.e propene since it is an alkene.
3. The substituent group attached is methyl i.e CH3. In this case, we'll start counting from the side of the double bond being the functional group. Therefore, the methyl group i.e CH3 is at carbon 2.
4. Therefore, the name of the compound is:
2–methylpropene
