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insens350 [35]
3 years ago
10

Which of the following mixture types is characterized by the settling of particles?

Chemistry
1 answer:
torisob [31]3 years ago
8 0
The answer is B. Suspension. Suspension mixtures are composed of two or more materials mixed together wherein the solute particles are usually larger than those found in a solution or colloid. In cases of solid-fluid suspension mixtures, the solid solute particles tend to settle at the bottom of the mixture after some time.
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Enter a range of values for x, 2x+10, 14 ​
PIT_PIT [208]

Answer:

62 degrees and 15.

Explanation:

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An iron smoothing out the wrinkles in pants ? CONVECTION,RADIATION,CONDUCTION?
nexus9112 [7]

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Represent the decomposition of aluminum oxide using the same number of atoms of molecules as are
pantera1 [17]

Answer:

Decomposition of aluminium oxide forms  aluminium atoms and  oxygen atoms.

Explanation:

<u>Decomposition reaction:</u>

When a single compound break down into two or more simpler products.

For example "AB" reactant undergoes decomposition to form "A" and "B" products.

The chemical reaction is as follows.

AB\rightarrow A+B

The given compound is aluminium oxide.

The decomposition reaction of aluminium oxide is a follows.

Al_{2}O_{3}\rightarrow Al+O_{2}

The balanced equation is as follows.

2Al_{2}O_{3}\rightarrow 4Al+3O_{2}

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4 0
3 years ago
How many moles of pcl5 can be produced from 23.0 g of p4 (and excess cl2)?
Masja [62]
The balanced equation for the above reaction is as follows
P4 + 10Cl2 —> 4PCl5
P4 is the limiting reactant. Stoichiometry of P4 to PCl5 is 1:4
The mass of P4 reacted = 23.0 g
Number of P4 moles = 23.0 g/ 124 g/mol = 0.185 mol
According to the stoichiometry the number of PCl5 moles produced are 4 times the amount of P4 moles reacted
Therefore PCl5 moles = 0.185 x 4 = 0.74 mol
3 0
3 years ago
How many Faraday is needed to deposit 0.2 g of Calcium (Ca) from CaCl2 solution using electrolysis process.
EastWind [94]

Answer:

0.01 faraday

Explanation:

We'll begin by writing the balanced equation. This is illustrated below:

CaCl₂ (aq) —> Ca²⁺ (aq) + 2Cl¯ (aq)

Ca²⁺ (aq) + 2e —> Ca

Molar mass of Ca = 40 g/mol

Mass of Ca from the balanced equation = 1 × 40 = 40 g

1 mole of electron (e) = 1 faraday

2 moles of electrons (e) = 2 × 1 faraday

2 moles of electrons (e) = 2 faraday

From the balanced equation above,

40 g of Ca was deposited by 2 faraday.

Therefore, 0.2 g of Ca will be deposited by = (0.2 × 2)/40 = 0.01 faraday.

Thus, 0.01 faraday is needed for the reaction.

4 0
3 years ago
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