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mrs_skeptik [129]
3 years ago
15

Calculate the ph of a buffer solution that contains 0.25 M benzoic acid (c6h5co2h) and 0.15M sodium benzoate (c6h5coona) . Ka=6.

5×10-5
Chemistry
1 answer:
Anna11 [10]3 years ago
8 0

Answer:

4.0

Explanation:

we have a buffer system formed by a weak acid (benzoic acid C₆H₅O₂H) and its conjugate base (benzoate ion C₆H₅O₂⁻, coming from sodium benzoate C₆H₅O₂Na). Given the acid dissociation constant (Ka) for benzoic acid is 6.5 × 10⁻⁵, we can calculate the pH of the buffer solution using the Henderson-Hasselbach equation.

pH =pKa + log [base]/[acid]

pH =-log Ka + log [C₆H₅O₂⁻]/[C₆H₅O₂H]

pH =-log 6.5 × 10⁻⁵ + log (0.15 M/0.25 M) = 4.0

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Consider a piece of gold jewelry that weighs 9.85 g and has a volume of 0.675 cm3 . The jewelry contains only gold and silver, w
AlekseyPX

Answer:

61.5096 %

Explanation:

Let the amount of gold in the jewelry = x g

Let the amount of silver in the jewelry = y g

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x + y = 9.85 g    .................................1

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Given that:

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Thus, volume is:

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So,

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Solving 1 and 2, we get that:

<u>x = 6.0587 g</u>

<u>y = 3.7913 g</u>

So, mass % of gold:

<u>Mass % = (6.0587 / 9.85)×100 = 61.5096 %</u>

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3 years ago
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