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3 years ago

Ethylene glycol (antifreeze) has a density of 1.11 g/cm3. what is the volume in liters of 3.46 kg of ethylene glycol?

1 answer:

7 0

Density is a physical property which describes the mass of a substance per unit of volume of the substance. It is expressed as Density = m / V and it has units like g/cm^3. We use the density given to solve the problem.

3.46x10³ g / 1.11 g/cm³ = 3117.12 cm³ (1 L / 1000 cm³) =3.12 L

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Dvinal [7]

Explanation:

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3 years ago

Ethyl ethanoate undergoes following reaction [on the picture]

vichka [17]

<u>Answer:</u> The concentration of ethyl ethanoate at equilibrium is $0.653mol/dm^3$

<u>Explanation:</u>

Given values:

Equilibrium concentration of ethanol = $0.42mol/dm^3$

Equilibrium concentration of ethanoic acid = $0.42mol/dm^3$

$K_c=0.27$

The given chemical equation follows:

$CH_3COOC_2H_5+H_2O\rightleftharpoons C_2H_5OH+CH_3COOH$

The expression of $K_c$ for above equation follows:

$K_c=\frac{[C_2H_5OH][CH_3COOH]}{[CH_3COOC_2H_5]}$

Putting values in above expression, we get:

$0.27=\frac{0.42\times 0.42}{[CH_3COOC_2H_5]}$

$[CH_3COOC_2H_5]=\frac{0.42\times 0.42}{0.27}=0.653mol/dm^3$

Hence, the concentration of ethyl ethanoate at equilibrium is $0.653mol/dm^3$

5 0

3 years ago

I need help with this ASAP!!!

Rus_ich [418]

Your answer would be 6.4 because that’s how many times you visit dannyduncan69.com

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3 years ago

germanium -66 has a half-life of 2.5 hours. you have 35 grams of radioactive material. after 16 days, how much radioactive mater

Maru [420]

Hey there!

A half-life means after a certain amount of time, half of that substance will be gone/changed after that time.

How many half-lives are in 16 days?

Multiply 16 by 24 (to get the total hours) and divide that by 2.5.

That is 153.6 half-lives.

35(0.5)^(153.6) represents the equation for this.

Simplify this and get 8.88 x 10^(-45).

There will be 2.02 x 10^(-45)g of germanium-66 sample remaining after 16 days.

Hope this helps!

6 0

3 years ago

if it takes 54 mL of 0.1 NaOH to neutralize 125 mL of an HCL solution, what is the concentration of HCL?

alexira [117]

Answer:

0.0432 M

Explanation:

We are given;

Volume of NaOH as 54 mL

Molarity of NaOH as 0.1 M

Volume of HCl as 125 mL

We are required to determine the concentration of HCl

Step 1; We write a balanced equation for the reaction between NaOH and HCl

The balanced equation is given by;

NaOH(aq) + HCl(aq) → NaCl(aq) + H₂O(l)

Step 2: Determine the number of moles of NaOH

Moles = Volume × molarity

Therefore;

Moles of NaOH = 0.054 L × 0.1 M

= 0.0054 Moles

Step 3: We use the mole ratio to determine the moles of HCl

From the equation;

1 mole of NaOH reacts with 1 mole of HCl

Therefore;

Moles of NaOH = Moles of HCl

Thus; moles of HCl = 0.0054 moles

Step 4: Determine the concentration of HCl

We know that;

Molarity = Moles ÷ Volume

Therefore;

Molarity of HCl = 0.0054 moles ÷ 0.125 L

= 0.0432 M

Therefore, the concentration of HCl is 0.0432 M

6 0

3 years ago