Jose gets up from his seat on the bus to move closer to the front. Just as he begins to walk forward, the bus stops at a light.
2 answers:
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Answer:
C1/C2 = 0.213 or C2/C1 = 4.68
Explanation:
Please refer to the attached image for step by step explanation.
Answer:
E = 1.04*10⁻¹ N/C
Explanation:
Assuming no other forces acting on the proton than the electric field, as this is uniform, we can calculate the acceleration of the proton, with the following kinematic equation:
As the proton is coming at rest after travelling 0.200 m to the right, vf = 0, and x = 0.200 m.
Replacing this values in the equation above, we can solve for a, as follows:
According to Newton´s 2nd Law, and applying the definition of an electric field, we can say the following:
F = mp*a = q*E
For a proton, we have the following values:
mp = 1.67*10⁻²⁷ kg
q = e = 1.6*10⁻¹⁹ C
So, we can solve for E (in magnitude) , as follows:
⇒ E = 1.04*10⁻¹ N/C
Answer:
F_B = 6.4*10^-13 N
Explanation:
The magnetic force on the electron, generated by the motion of the electron and the magnetic field is given by:
q: electron charge = 1.6*10^{-19}C
v: speed of the electron = 2.0*10^6 m/s
B: magnitude of the magnetic field = 2T
However, the direction of B and v are perpendicular between them. So, the angle between vectors is 90°. The magnitude of the magnetic force is:
You replace the values of q, v and B in the last equation:
hence, the magnetic force on the electron is 6.4*10^-23 N