The impact speed will be
v^2 = 2*9.8*1.3
v^2 = 25.48
v= 5.04 m/s
A) change in ht after 180m = 180 * sin(4-deg.) = 12.56m
net work done by gravity on the cyclist = mass * gravity * height diff.
= 85 * 9.8 * 12.56
= 10470J
= 10.5kJ
B) Kinetic energy = 1/2 * mass * vel.^2 = work done by gravity = 10470J
vel.^2 = 10470 * 2 / 85 = 246.4
vel. = 15.7m/s
Answer:
The minimum force to start the block moving up the wall = 49 N
Explanation:
Friction: This is the force that tend to oppose the motion of two bodies in contact. The S.I unit of frictional force is Newton (N)
The minimum force required to start the block moving up the wall = Frictional Force.
I.e F = Frictional force.
And, F = μR..........................Equation 1
Where μ = coefficient of static friction, R = Normal reaction.
But R = mg ( on a level surface).................. Equation 2
Where m = mass, g = acceleration due to gravity.
Given: m = 10 kg,
Constant: g = 9.8 m/s²
substituting these values into Equation 2
R = 10 × 9.8
R = 98 N.
Also given: μ = 0.50
Substituting these values into equation 1
F = 98 × 0.5
F = 49 N.
Therefore The minimum force to start the block moving up the wall = 49 N
Answer:
![(a)\ F_{No} = [P_{No} - \frac{P_{area}}{2}]* A](https://tex.z-dn.net/?f=%28a%29%5C%20F_%7BNo%7D%20%3D%20%5BP_%7BNo%7D%20-%20%5Cfrac%7BP_%7Barea%7D%7D%7B2%7D%5D%2A%20A)

Explanation:
Given
---- Altitude of container in Denver
-- Surface Area of the container lid
--- Air pressure in Denver
--- Air pressure in New Orleans
<em>See comment for complete question</em>
Solving (a): The expression for 
Force is calculated as:

The force in New Orleans is:

Since the inside pressure is half the pressure at sea level, then:

Where
--- Standard Pressure
Recall that:

This gives:
![F_{No} = [P_{No} - \frac{P_{area}}{2}]* A](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5BP_%7BNo%7D%20-%20%5Cfrac%7BP_%7Barea%7D%7D%7B2%7D%5D%2A%20A)
Solving (b): The value of 
In (a), we have:
![F_{No} = [P_{No} - \frac{P_{area}}{2}]* A](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5BP_%7BNo%7D%20-%20%5Cfrac%7BP_%7Barea%7D%7D%7B2%7D%5D%2A%20A)
Where



So, we have:
![F_{No} = [100250 - \frac{101000}{2}] * 0.0155](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5B100250%20-%20%5Cfrac%7B101000%7D%7B2%7D%5D%20%2A%200.0155)
![F_{No} = [100250 - 50500] * 0.0155](https://tex.z-dn.net/?f=F_%7BNo%7D%20%3D%20%5B100250%20-%2050500%5D%20%2A%200.0155)

