The answer is D. 64. Have a nice day!
If there is one table (t=1) then 6 chairs (c=6) can be placed around the table, 2 along the length on each side and 1 at each end.
When t=2, and the tables are end to end (joined at their width) c=10, that is, 4 chairs on each side of the double table and 1 at each end. Each time a table is added c increases by 4 so we can write c=4t+2 the constant 2 being the single chair at each end. If the tables are separated then c=6t.
The GCF (Greatest Common Factor) of 25 and 65 is 5. So, we can divide both numbers by 5.
25 / 5 = 5
65 / 5 = 13
Now, put it into a fraction.
5/13
This cannot be simplified any further.
Best of Luck!