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3 years ago

6

What is nine less then the product of a number squared and ten

1 answer:

murzikaleks [220]3 years ago

6 0

A number squared would be x squared (x^2)
The product of x squared and ten is 10x^2
Then subtract nine

10x^2 - 9

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Write a fact with the same sum as 7+ 5.

lisov135 [29]

0+12, 11+1, 4x3, 6x2, etc.

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3 years ago

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Solve the system of linear equations below. 2x + 3y = 2 x + 6y = 4 x........A.X=0, y =2/3..B..x =2, y = -2/3...C..x=4/3, y=2/9..

Bogdan [553]

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is what i got sorry if it don't help</span></span></span>

3 0

3 years ago

1. Factor the trinomial: x2 - 7x - 8

telo118 [61]

1. A

-8+1=7 and 8*1=8

2. A

-5*8= -40 and 8-5= 3

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3 years ago

What is 3/4 of 50 for a math assignment.

Burka [1]

Answer:

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Step-by-step explanation:

multiply the two numbers if their is an “of” in the statement

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3 years ago

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The ages of 11 students enrolled in an on-line macroeconomics course are given in the following steam-and-leaf display:

blsea [12.9K]

Answer:

The standard deviation of the age distribution is 6.2899 years.

Step-by-step explanation:

The formula to compute the standard deviation is:

$SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}$

The data provided is:

X = {19, 19, 21, 25, 25, 28, 29, 30, 31, 32, 40}

Compute the mean of the data as follows:

$\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}$

$=\frac{1}{11}\times [19+19+21+...+40]\\\\=\frac{299}{11}\\\\=27.182$

Compute the standard deviation as follows:

$SD=\sqrt{\frac{1}{n}\sum\limits^{n}_{i=1}{(x_{i}-\bar x)^{2}}}$

$=\sqrt{\frac{1}{11-1}\times [(19-27.182)^{2}+(19-27.182)^{2}+...+(40-27.182)^{2}]}}\\\\=\sqrt{\frac{395.6364}{10}}\\\\=6.28996\\\\\approx 6.2899$

Thus, the standard deviation of the age distribution is 6.2899 years.

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2 years ago