I need help plz with this.

Sixty percent of the customers who go to Sears Auto Center for tires buy four tires and 22% buy two tires. Moreover, 14% buy few

Bezzdna [24]

Answer:

There is a 4% probability that a customer buys three tires.

Step-by-step explanation:

We have those following percentages

60% buy four tires. This is also the probability that someone buys four tires.

22% buy two tires

14% buy fewer than two tires(one or none).

P% buy three tires

The sum of the percentages must be 100%.

So

$60 + 22 + 14 + P = 100$

$96 + P = 100$

$P = 4$

There is a 4% probability that a customer buys three tires.

8 0

3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

A car tire is spinning a complete revolution every 0.60 seconds. The valve stem is 2 inches above ground at its lowest point and

finlep [7]

Answer:

Step-by-step explanation:

What is the amplitude, ||, of the height and co-height functions for this car tire

|| = 6

Let () represent the co-height function after rotation by radians, and let () represent the height function after rotation by radians. Write functions for the co-height and for the height in terms of .

() = ()

The co-height graphs are the same but translated 2 inches upward

so our function is:

() = () + 2 or

() = () + 2

5 0

3 years ago

Which of the following is the solution set to the equation: 2x(x-3)(4x+1)=0?

Troyanec [42]

Answer:

(1) {-1/4, 0, 3}

Step-by-step explanation:

Step 1: Factor left side of equation.

2x(4x+1)(x−3)=0

Step 2: Set factors equal to 0.

2x=0 or 4x+1=0 or x−3=0

x=0 or x= −1/4 or x=3

3 0

3 years ago

Find the median of 30 , 40, 35, 50 and 55 degrees angle measures

ELEN [110]

We know that
the median is the middle number when listed in order from least to greatest.

step 1
listed in order from least to greatest
[30,40, 35, 50, 55]--------> [30, 35, 40, 50, 55]

step 2
find the middle number

the middle number is 40

therefore

the answer is
the median is 40°

6 0

3 years ago