A sled and a rider slide down a snow-covered hill that makes

उत्तोलक हुन् ?

Verdich [7]

Answer:

The length of the load arm is 3 m

The length of the effort arm is 15 m

Spoons and scissors are class 1 levers

Explanation:

The data given in the force diagram of the lever (machine) are;

The length of the lever = 18 m = (Length of effort arm) + (Length of load arm)

The force applied at the effort = 100 N

The load lifted by the lever = 500 N

The mechanical advantage, MA is given as follows;

MA = Load/Effort = (Length of effort arm)/(Length of load arm)

∴ MA = 500 N/(100 N) = 5

Let 'x' represent the length of the effort arm, and let 'y', represent the length of the load arm, we have;

x + y = 18...(1) (given)

MA = 5 = x/y

∴ x = 5·y...(2)

Substituting the value of 'x' in equation (1) with x = 5·y gives;

x + y = 5·y + y = 6·y = 18

∴ y = 18/6 = 3

y = 3

The length of the load arm, y = 3 m

x = 5·y = 5 × 3 = 15

x = 15

The length of the effort arm, x = 15 m

When lifting food with a spoon, the fulcrum, which can be taken as the edge of the plate or the supporting finger, is in between bowl of the spoon and the point of application of the thumb towards the extremities of the spoon handle

Therefore a spoon is a class 1 lever

The pivot of a scissors is in between the item being cut (the load) and the holes where the finger applies an effort

Therefore, a scissors is a class 1 lever.

4 0

2 years ago

Jax went to the vet and the scale reads 9 pounds. what does this mean?

makkiz [27]

if jax is an animal it means it is under weight. and if its a human there severly anorexic

8 0

3 years ago

A spring with k = 500 N/m stores 704 J. How far is it extended from the equilibrium position

kaheart [24]

Given that:

k = 500 n/m,

work (W) = 704 J

spring extension (x) = ?

we know that,

Work = (1/2) k x²

704 = (1/2) × 500 × x²

x = 1.67 m

A spring stretched for 1.67 m distance.

4 0

3 years ago

An ion with charge of Q = +3.2 x 10-19 C is in a region where a uniform electric field of magnitude E = 5.0 X 105 V/m is perpend

san4es73 [151]

Answer:

option C

Explanation:

given,

Q = +3.2 x 10⁻¹⁹ C

E = 5.0 X 10⁵ V/m

B = 0.80 T

ion's acceleration is zero

when acceleration is zero the magnitude of both the forces becomes equal.

q E = q V B

v = $\dfrac{E}{B}$

v= $\dfrac{5 \times 10^5}{0.80}$

v = 6.25 × 10⁵ m/s ≈ 6.3 × 10⁵ m/s

hence, the correct answer is option C

8 0

3 years ago

A simple pendulum is used to determine the acceleration due to gravity at the surface of a planet. The pendulum has a length of

SVEN [57.7K]

Answer:

Acceleration due to gravity is 20 $m/sec^2$

So option (E) will be correct answer

Explanation:

We have given length of the pendulum l = 2 m

Time period of the pendulum T = 2 sec

We have to find acceleration due to gravity g

We know that time period of pendulum is given by

$T=2\pi \sqrt{\frac{l}{g}}$

$2=2\times 3.14 \sqrt{\frac{2}{g}}$

$0.3184= \sqrt{\frac{2}{g}}$

Squaring both side

$0.1014= {\frac{2}{g}}$

$g=19.71=20m/sec^2$

So acceleration due to gravity is 20 $m/sec^2$

So option (E) will be correct answer.

8 0

3 years ago