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Maru [420]
2 years ago
8

Which set of terms is in the proper order, from left to right, for labeling the

Physics
1 answer:
Rufina [12.5K]2 years ago
3 0
A. Base , salt , water,acid
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If a ball is thrown into the air with a velocity of 36 ft/s, its height (in feet) after t seconds is given by y = 36t − 16t2. fi
Juliette [100K]
Height (y) = 36t - 16t^2, where t = time in seconds (s).
Our height (y) after 1s = 36(1) - 16(1)^2
y = 36 - 16 = 20 ft
So it reached a height of 20 ft during that 1 second, which means that at that 1 second it had a velocity of 20ft/s, since v = d(distance)/t = 20ft/1s
6 0
3 years ago
Which of the rolling statement is not true about proper tire care? A. If you see a weaver bar across the width of the tread. B.
skad [1K]
The correct answer should be <span>A. If you see a wear bar across the width of the tread, it's time to change the tire

This is an incorrect sentence because you should change a tire before you see the wear bar. At the time you see the bar, you should've already changed it. </span>
7 0
3 years ago
Siven an element's atomic number and mass number, how can you tell the number of protons and neutrons in its nucleus?
sukhopar [10]
It would be the first option.

Explanation-
The number of protons is equal to the atomic number the number of neutrons is the mass minus the atomic number.
3 0
3 years ago
Read 2 more answers
Avi, a gymnast, weighs 40 kg. She is jumping on a trampoline that has a spring constant value of 176,400 StartFraction N over m
Fiesta28 [93]

Answer:

9

Explanation:

6 0
3 years ago
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Suppose a certain jet plane creates an intensity level of 124 dB at a distance of 5.01 m. What intensity level does it create on
Zolol [24]

Answer:71 dB

Explanation:

Given

sound Level \beta _1=124 dB

distance r_1=5.01 m

From sound Intensity

\beta =10dB\log (\frac{I_1}{I_0})

124=10dB\log (\frac{I_1}{I_0})

12.4=\log (\frac{I_1}{I_0})

I_1=(1\times 10^{-12})\times 10^{12.4}

I_1=2.51 W/m^2

we know Intensity I\propto ^\frac{1}{r^2}

I_1r_1^2=I_2r_2^2

I_2=I_1(\frac{r_1}{r_2})^2

I_2=2.51\cdot (\frac{5.01}{2.25\times 10^3})^2

I_2=1.24\times 10^{-5} W/m^2

Sound level corresponding to I_2

\beta _2=10\log (\frac{I_2}{I_0})

\beta _2=10\log (\frac{1.24\times 10^{-5}}{1\times 10^{-12}})

\beta _2=70.93\approx 71 dB

6 0
3 years ago
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