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nikitadnepr [17]
3 years ago
15

........................................

Physics
1 answer:
valina [46]3 years ago
6 0

Answer:

Explanation:

I am sorry but please give detailed question

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Answer:

\displaystyle \Delta x=1.74\ m

Explanation:

<u>Elastic Potential Energy </u>

Is the energy stored in an elastic material like a spring of constant k, in which case the energy is proportional to the square of the change of length Δx and the constant k.

\displaystyle PE = \frac{1}{2}k(\Delta x)^2

Given a rubber band of a spring constant of k=5700 N/m that is holding potential energy of PE=8600 J, it's required to find the change of length under these conditions.

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Calculating:

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\boxed{\displaystyle \Delta x=1.74\ m}

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