Answer:
15 and Increasing
Explanation:
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The goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground
Explanation:
Consider the vertical motion of ball,
We have equation of motion v = u + at
Initial velocity, u = u sin θ
Final velocity, v = 0 m/s
Acceleration = -g
Substituting
v = u + at
0 = u sin θ - g t

This is the time of flight.
Consider the horizontal motion of ball,
Initial velocity, u = u cos θ
Acceleration, a =0 m/s²
Time,
Substituting
s = ut + 0.5 at²

This is the range.
In this problem
u = 30 m/s
g = 9.81 m/s²
θ = 45° - For maximum range
Substituting

Maximum horizontal distance traveled by ball without touching ground is 45.87 m, which is less than 95 m.
So the goalkeeper at his goal cannot kick a soccer ball into the opponent’s goal without the ball touching the ground
Answer:
low freezing point. high vapour pressure.
<em>HOPE</em><em> </em><em>IT</em><em> </em><em>WILL</em><em> </em><em>HELP</em><em> </em><em>U</em><em>! </em><em>!</em><em>!</em><em>!</em><em>!</em><em>!</em>
To solve this exercise it is necessary to take into account the concepts related to Tensile Strength and Shear Strenght.
In Materials Mechanics, generally the bodies under certain loads are subject to both Tensile and shear strenghts.
By definition we know that the tensile strength is defined as

Where,
Tensile strength
F = Tensile Force
A = Cross-sectional Area
In the other hand we have that the shear strength is defined as

where,
Shear strength
Shear Force
Parallel Area
PART A) Replacing with our values in the equation of tensile strenght, then

Resolving for F,

PART B) We need here to apply the shear strength equation, then



In such a way that the material is more resistant to tensile strength than shear force.
Answer:
3 L
Explanation:
From the question given above, the following data were obtained:
Initial volume (V₁) = 2 L
Initial pressure (P₁) = 0.75 atm
Final pressure (P₂) = 0.5 atm
Final volume (V₂) =?
Using the Boyle's law equation, the new volume (i.e final volume) of the Ne gas can be obtained as:
Initial volume (V₁) = 2 L
Initial pressure (P₁) = 0.75 atm
Final pressure (P₂) = 0.5 atm
Final volume (V₂) =?
P₁V₁ = P₂V₂
0.75 × 2 = 0.5 × V₂
1.5 = 0.5 × V₂
Divide both side by 0.5
V₂ = 1.5 / 0.5
V₂ = 3 L
Thus, the new volume of the Ne gas is 3 L