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kow [346]
3 years ago
12

Arman, Narek and Areg are brothers. Arman's age is five times as much as Areg's age and Narek is 12 years elder than Areg. If Na

rek is 15 years old, how old are Areg and Arman?
Mathematics
1 answer:
Bumek [7]3 years ago
4 0
Armans age : x
Aregs age: y

X = 5y
(15 - 12) = y. They said narek is 12 years older than areg so you deduct 12 years from nareks age which is 15.

So therefore y = 3. So Areg is 3 years old.

Since we know that y = 3
X = 5(3)
X = 15

So therefore Arman is 15 years and Areg is 3 years.

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Graph XY with endpoints X(5,−2) and Y(3,−3) and its image after a reflection in the x-axis and then a rotation of 270 degrees ab
DerKrebs [107]

Answer:

  X''(2, -5), Y''(3, -3)

Step-by-step explanation:

You know that reflection in the x-axis changes the sign of the y-coordinate. Points that used to be above the axis are now below by the same amount, and vice versa.

Rotation counterclockwise by 270° is the same as clockwise rotation by 90°. That maps the coordinates like this:

  (x, y) ⇒ (y, -x)

The two transformations together give you ...

  (x, y) ⇒ (x, -y) ⇒ (-y, -x) . . . . . . . . equivalent to reflection across y=-x.

Using this mapping, we have ...

  X(5, -2) ⇒ X''(2, -5)

  Y(3, -3) ⇒ Y''(3, -3) . . . . . . on the equivalent line of reflection, so invariant

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The attachment shows the original segment in red, the reflected segment in purple, and the rotated segment in blue. The equivalent line of reflection is shown as a dashed green line.

8 0
3 years ago
If 2.5 mol of dust particles were laid end to end along the equator, how many times would they encircle the planet? The circumfe
Natalka [10]

Answer:

They encircle the planet 3.76\times 10^{11} times.

Step-by-step explanation:

Consider the provided information.

We have 2.5 mole of dust particles and the Avogadro's number is 6.022\times 10^{23}

Thus, the number of dust particles is:

2.5\times 6.022\times 10^{23}=15.055\times 10^{23}

Diameter of a dust particles is 10μm and the circumference of earth is 40,076 km.

Convert the measurement in meters.

Diameter: 10\mu m\times \frac{10^{-6}m}{\mu m} =10^{-5}m

If we line up the particles the distance they could cover is:

15.055\times 10^{23}\times 10^{-5}=15.055\times 10^{18}=1.5055\times 10^{19}

Circumference in meters:

40,076km\times \frac{1000m}{1km}=40,076,000 m

Therefore,

\frac{1.5055\times 10^{19}}{40,076,000} = 3.76\times 10^{11}

Hence, they encircle the planet 3.76\times 10^{11} times.

8 0
3 years ago
Anybody know this answer?
AveGali [126]

      3

19  _

      5 is the answer

7 0
3 years ago
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Please help! I’ll mark brainliest
Usimov [2.4K]

Answer: 19 ≥ 3z + 1 ≥ - 5

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