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3 years ago

7

What is the mass percent of potassium sulfate in solution if 78g of potassium sulfate is dissolved in 500 mL of water? (The dens

ity of water is 1.00 g/mL)

1 answer:

Debora [2.8K]3 years ago

6 0

Answer:

13.5 %

Explanation:

First we<u> calculate the mass of 500 mL of water</u>, using <em>its density</em>:

Volume * Density = Mass

500 mL * 1.00 g/mL = 500 g

Then we <u>calculate the mass percent of potassium sulfate</u>, using the formula:

Mass of Potassium Sulfate / Total Mass * 100%

78 g / (78 + 500) g * 100 % = 13.5 %

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If 12 gallons of gasoline cost $34.68, what is the unit price per gallon?

chubhunter [2.5K]

The answer is $2.89.

Since it’s asking for the unit price of one gallon and you have the total ($34.68 and 12 gallons), you would divide $34.68 from 12, which gives you $2.89.

34.68/12 = 2.89

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2 years ago

A tire at 21°C has a pressure of 0.82 atm. Its temperature decreases to –3.5°C. If there is no volume change in the tire, what i

IRINA_888 [86]

Answer : The pressure after the temperature change is, 0.752 atm

Explanation :

Gay-Lussac's Law : It is defined as the pressure of the gas is directly proportional to the temperature of the gas at constant volume and number of moles.

$P\propto T$

or,

$\frac{P_1}{T_1}=\frac{P_2}{T_2}$

where,

$P_1$ = initial pressure = 0.82 atm

$P_2$ = final pressure = ?

$T_1$ = initial temperature = $21^oC=273+21=294K$

$T_2$ = final temperature = $-3.5^oC=273+(-3.5)=269.5K$

Now put all the given values in the above equation, we get:

$\frac{0.82atm}{294K}=\frac{P_2}{269.5K}$

$P_2=0.752atm$

Thus, the pressure after the temperature change is, 0.752 atm

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4 years ago

What is a tolerant of sea spray? I NEED HELP WITH THIS QUESTION !!! Answer fast for 20 poins

DedPeter [7]

Answer:

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3 years ago

hoa [83]

Answer:

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3 years ago

Calculate %ic of the interatomic bonds for the intermetallic compound al6mn. on the basis of this result, what type of interatom

pashok25 [27]

Answer : % ionic character is 0.20%

Bonding between the two metals will be purely metallic.

Explanation: For the calculation of % ionic character, we use the formula

$\% \text{ ionic character}= [1-e^{\frac{-(X_A-X_B)^2)}{4}}]\times(100\%)$

where $X_A$ & $X_B$ are the Pauling's electronegativities.

The table attached has the values of electronegativities, by taking the values of Al and Mn from there,

$X_{Al}=1.61$

$X_{Mn}=1.55$

Putting the values in the electronegativity formula, we get

$\% \text{ ionic character}= [1-e^{\frac{-(1.61-1.55)^2)}{4}}]\times(100\%)$

= 0.20%

Now, there are 3 types of inter atomic bonding

1) Ionic Bonding: It refers to the chemical bond in which there is complete transfer of valence electrons between atoms

2) Covalent Bonding: It refers to the chemical bond involving the sharing of electron pairs between 2 atoms.

3) Metallic Bonding: It refers to the chemical bond in which there is an electrostatic force between the positively charged metal ions and delocalised electrons.

In $Al_6Mn$ compound, the % ionic character is minimal that is $\sim$ 0.20% and there are two metal ions present, therefore this compound will have metallic bonding.

8 0

3 years ago