What is the mass percent of potassium sulfate in solution if 78g of potassium sulfate is dissolved in 500 mL of water? (The dens ity of water is 1.00 g/mL)
1 answer:
Answer:
13.5 %
Explanation:
First we<u> calculate the mass of 500 mL of water</u>, using <em>its density</em>:
500 mL * 1.00 g/mL = 500 g Then we <u>calculate the mass percent of potassium sulfate</u>, using the formula:
Mass of Potassium Sulfate / Total Mass * 100%
78 g / (78 + 500) g * 100 % = 13.5 %
You might be interested in
PH= log[H3O+] 10.25=log [H3O+] [H3O+] = 10^10.25 [H3O+]= 1.778 ×10^10
The molecule that is nonpolar is CO2
D. to mine for specific minerals
Density = Mass / Volume V = 1.00 * 4.00 * 2.50 = 10 cm³ 22.57 g/cm³ = Mass / 10 cm³ M = 22.57 g/cm³ * 10 cm³ M = 225.7 g Answer: The mass of the block of osmium is 225.7 g.
They are particular solids.