We are unable to answer this question without being able to see the graph.
The equation of the line in standard form is x + 4y = 8
<h3>How to determine the line equation?</h3>
From the question, the points are given as
(0, 2) and (8, 0)
To start with, we must calculate the slope of the line
This is calculated using
Slope = (y₂ - y₁)/(x₂ - x₁)
Where
(x, y) = (0, 2) and (8, 0)
Substitute the known parameters in Slope = (y₂ - y₁)/(x₂ - x₁)
So, we have
Slope = (0 - 2)/(8 - 0)
Evaluate
Slope = -1/4
The equation of the line can be calculated using as
y - y₁ = m(x + x₁)
Where
(x₁, y₁) = (0, 2)
and
m = slope = -1/4
Substitute the known values in the above equation
So, we have the following equation
y - 2 = -1/4(x - 0)
This gives
y - 2 = -1/4x
Rewrite as
1/4x + y = 2
Multiply by 4
x + 4y = 8
Hence, the line has an equation of x + 4y = 8
Read more about linear equations at
brainly.com/question/4074386
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Answer:
x^3-7
Step-by-step explanation:
The cube of a number means that it is to the power of 3 and 7 is subtracted is just the number cubed and then minus 7.
Answer:
31.82% probability that this day would be a winter day
Step-by-step explanation:
We use the conditional probability formula to solve this question. It is

In which
P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
P(A) is the probability of A happening
In this question:
Event A: Rain
Event B: Winter day
Probability of rain:
0.42 of 0.25(winter), 0.23 of 0.25(spring), 0.16 of 0.25(summer) or 0.51 of 0.25(fall).
So

Intersection:
Rain on a winter day, which is 0.42 of 0.25. So

If you were told that on a particular day it was raining in Vancouver, what would be the probability that this day would be a winter day?

31.82% probability that this day would be a winter day
9x3x8/92=2.347 and that rounded =2.35.