At what temperature would a gas have a volume of 13.5 L at a pressure of 0.723 atm, if it had a volume of 17.8 L at a pressure o
1 answer:
Answer : The initial temperature of gas would be, 269.7 K
Explanation :
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 0.723 atm
= final pressure of gas = 0.612 atm
= initial volume of gas = 13.5 L
= final volume of gas = 17.8 L
= initial temperature of gas = ?
= final temperature of gas =
Now put all the given values in the above equation, we get:
Thus, the initial temperature of gas would be, 269.7 K
You might be interested in
The time required to reduce the concentration from 0.00757 M to 0.00180 M is equal to 1.52 × 10⁻⁴ s. The half-life period of the reaction is 9.98× 10⁻⁵s.
<h3>What is the rate of reaction?</h3>The rate of reaction is described as the speed at which reactants are converted into products. A catalyst increases the rate of the reaction without going under any change in the chemical reaction.
Given the initial concentration of the reactant, C₀= 0.00757 M
The concentration of reactant after time t is C₁= 0.00180 M
The rate constant of the reaction, k = 37.9 M⁻¹s⁻¹
For the first-order reaction:
0.00180 = 0.00757 - (37.9) t
t = 1.52 × 10⁻⁴ s
The half-life period of the reaction:
Half-life of the reaction = 9.98 × 10⁻⁵s
Learn more about the rate of reaction, here:
#SPJ1
The balanced equation would be
Zn reacts with Cu solution according to the following equation:
In the reaction, is reduced according to the following:
While Zn is oxidized according to the following:
Thus, giving the overall equation of;
More oxidation-reduction equations can be found here: brainly.com/question/13699873
#SPJ1