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gladu [14]
3 years ago
15

Help pretty please :)

Chemistry
1 answer:
Hatshy [7]3 years ago
4 0
The answer is 15 bc you multiply the coefficient but the subscript
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Dos vehículos colisionan. Se sabe que antes del choque el vehículo 1 de masa "m", se desplazaba horizontalmente hacia la derecha
BabaBlast [244]

Answer:

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Explanation:

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Is material that has a density of 0.2g/ml good for building a bridge or for making couch cushions
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D = 0.2 g / ml = 0.2 g / cm³
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Answer: Material that has a density of 0.2 g/ml ( 0.2 g/cm³ ) is good for making couch cushions. 
8 0
3 years ago
Read 2 more answers
Table salt is also known as sodium chloride, because it is
Mnenie [13.5K]

Sodom chloride is an ionic compound.

<h3>What is sodium chloride?</h3>

Sodium chloride is a compound that is formed by the combination of sodium and chlorine atoms. The compound is ionic as the ions of the atoms combine. Sodium looses one electron that can now be gained by chlorine.

Since the compound is ionic, it has a high melting and boiling point. This implies that the compound could melt as high as 801 degrees centigrade. The boiling point of the compound is much higher.

We can represent the compound using the ball and stick or the space filling model. The ball and stick model of sodium chloride has been shown in the image attached to this answer.

Learn more about ball and stick model:brainly.com/question/17217225

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6 0
1 year ago
Write me a brief description of a Nerve Signal. (Only one sentence)
astraxan [27]

Description of a nerve signal

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7 0
3 years ago
How many grams of sulfuric acid is needed to neutralize 380 ml of solution with pH = 8.94
erma4kov [3.2K]

Answer : The mass of sulfuric acid needed is 16.23\times 10^{-5}g.

Solution : Given,

pH = 8.94

Volume of solution = 380 ml = 380\times 10^{-3}      (1ml=10^{-3}L)

Molar mass of sulfuric acid = 98.079 g/mole

As we know,

pH+pOH=14\\pOH=14-8.94=5.06

pOH=-log[OH^-]

5.06=-log[OH^-]

[OH^-]=0.00000871=8.71\times 10^{-6}mole/L

Now we have to calculate the moles of OH^-.

Formula used : Moles=Concentration\times Volume

\text{ Moles of }[OH^-]=\text{ Concentration of }[OH^-]\times Volume\\\text{ Moles of }[OH^-]=(8.71\times 10^{-6}mole/L)\times (380\times 10^{-3}L)=3309.8\times 10^{-9}moles

For neutralization, equal number of moles of H^+ ions will neutralize same number of OH^- ions.

\text{ Moles of }[OH^-]=\text{ Moles of }[H^+]=3309.8\times 10^{-9}moles

As, H_2SO_4\rightarrow 2H^++SO^{2-}_4

From this reaction, we conclude that

2 moles of H^+ ion is given by the 1 mole of H_2SO_4

3309.8\times 10^{-9} moles of H^+ ion is given by \frac{3309.8\times 10^{-9}}{2}=1654.9\times 10^{-9} moles of H_2SO_4

Now we have to calculate the mass of sulfuric acid.

Mass of sulfuric acid = Moles of H_2SO_4 × Molar mass of sulfuric acid

Mass of sulfuric acid = (1654.9\times 10^{-9}moles)\times (98.079g/mole)=162310.94\times 10^{-9}=16.23\times 10^{-5}g

Therefore, the mass of sulfuric acid needed is 16.23\times 10^{-5}g.

3 0
3 years ago
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