Answer:
x=(10+m)/3
Step-by-step explanation:
3x-m=10
3x=10+m
x=(10+m)/3
Answer:
It will take Shanti 150 square inches of paper to wrap the gifts
Step-by-step explanation:
Shanti wraps the gift she is taking to a friend's birthday party. She doesn't have very much paper, so she does not overlap any of the edges. The side lengths of the cube are all 5in.
How much paper did it take to cover the gift?
Solution
To solve this, you will find the surface area of a cube
Surface area of a cube = 6a^2
Where,
a=side length of the cube
a= 5 in
a^2=a × a
=5 × 5
=25 in^2
a^2=25 in^2
Surface area of a cube = 6a^2
=6 × 25 in^2
=150 in^2
It will take Shanti 150 square inches of paper to wrap the gifts
To determine the scale factor of the dilation, we determine the distances between the endpoints of the two lines through the equation,
d = √(x₂ - x₁)² + (y₂ - y₁)²
Substituting the known values.
Line Segment 1: d = √(1 - 2)² + (4 - 8)² = 4.123
Line Segment 2: d = √(18 - 14)² + (12 - 1)² = 11.70
Dividing the answers will give us 0.352
Answer:
B.
Step-by-step explanation:
Well we know that
so we can get the 2 outside of the radical
and we can get the x^2 outside too.
and we also can get y outside.
so we have:
![2x^{2}y\sqrt[5]{7xy^3}](https://tex.z-dn.net/?f=2x%5E%7B2%7Dy%5Csqrt%5B5%5D%7B7xy%5E3%7D)
Answer:
2/π ≈ 0.637 m/s
Step-by-step explanation:
The rate of change of area with respect to time is ...
A = πr²
dA/dt = 2πr·dr/dt
Filling in given values in the above equations, we can find r and dr/dt.
25π = πr² ⇒ r = 5
20 = 2π·5·dr/dt
dr/dt = 20/(10π) = 2/π . . . . meters per second
The radius is increasing at the rate of 2/π ≈ 0.637 meters per second.
