Then the speed of the rider is, v = 2m/s
The linear velocity of an object in a straight line is its speed.
The following is the relationship between linear and angular velocity:
v = rω
The circumference of the bicycle wheel is,
2r = 2
r = 0.318m
The angular velocity of the wheel is,
ω = 1rev/sec = 2rad/s
Then the speed of the rider is,
v = rω
v = 0.318×2π
v = 2m/s
Learn more about angular velocity here:
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I am so sorry, but I do not know what section you are talking about. I hope you find the answer.
Answer:
1.82 rad/s².
Explanation:
Applying,
α = (ω₂-ω₁)/t..................... Equation 1
Where α = angular acceleration of the fan blades, ω₂ = final angular velocity of the fan blades, ω₁ = initial angular velocity of the fan blades, t = time.
Given: ω₂ = 350 rpm = (350×0.1047) rad/s = 36.645 rad/s. ω₁ = 250 rpm = (250×0.1047) rad/s = 26.175 rad/s, t = 5.75 s.
Substitute into equation 1
α = (36.645-26.175)/5.75
α = 10.47/5.75
α = 1.82 rad/s².
Hence the magnitude of the angular acceleration of the fan blades = 1.82 rad/s²