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juin [17]
2 years ago
14

An object with mass 80 kg moved in outer space. When it was at location <7, -34, -7> its speed was 14.0 m/s. A single cons

tant force <200, 460, -150> N acted on the object while the object moved to location <12, -42, -11> m. What is the speed of the object at this final location?
Physics
1 answer:
Sergio [31]2 years ago
7 0

Answer:

W = -2080 J

Explanation:

initial position vector of the object is given as

r_i = 7\hat i - 34\hat j - 7 \hat k

similarly final position vector is given as

r_f = 12\hat i - 42\hat j - 11\hat k

now the displacement of the object is given as

\vec d = \vec r_f - \vec r_i

now we will have

\vec d = (12\hat i - 42\hat j - 11\hat k) - (7\hat i - 34\hat j - 7 \hat k)

\vec d = 5\hat i - 8\hat j- 4\hat k

now the force on the object is given as

\vec F = (200\hat i + 460 \hat j - 150 \hat k)

so here in order to find the work done

W = \vec F . \vec d

W = (200\hat i + 460 \hat j - 150 \hat k). (5\hat i - 8\hat j- 4\hat k)

W = 1000 - 3680 + 600 = -2080 J

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