1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Galina-37 [17]
3 years ago
10

Use the information to answer the following question.

Chemistry
2 answers:
d1i1m1o1n [39]3 years ago
6 0

Answer: D

Explanation:

jolli1 [7]3 years ago
4 0
I think the answer is c
You might be interested in
If 17. 6 g of hcl are used to produce a 14. 5 l solution, what is the ph of the solution?.
kati45 [8]

This problem is providing us with the mass of hydrochloric acid and the volume of solution and asks for the pH of the resulting solution, which turns out to be 1.477.

<h3>pH calculations</h3>

In chemistry, one can calculate the pH of a solution by firstly obtaining its molarity as the division of the moles of solute by the liters of solution, so in this case for HCl we have:

M=\frac{17.6g*\frac{1mol}{36.46g} }{14.5L} \\\\M=0.0333 M

Next, due to the fact that hydrochloric acid is a strong acid, we realize its concentration is nearly the same to the released hydrogen ions to the solution upon ionization. Thereby, the resulting pH is:

pH=-log(0.0333)\\\\pH=1.477

Which conserves as much decimals as significant figures in the molarity.

Learn more about pH calculations: brainly.com/question/1195974

3 0
2 years ago
For the reaction co(g)+2h2(g)&lt;-&gt;ch3oh(g) at 700. k, equilibrium concentrations are [h2] = 0.072 m, [co] = 0.020 m, and [ch
SVETLANKA909090 [29]
The balanced equation for the reaction is
CO(g) + 2H₂(g) ⇄ CH₃<span>OH(g)

Since given concentrations are at equilibrium state, the expression for the equilibrium constant, k can be written as
   k = [</span>CH₃OH(g)] / [CO(g)] [H₂(g) ]²

By substitution,
   k = 0.030 M / 0.020 M x (<span>0.072 M</span>)²
   k = 289.35 M⁻²
6 0
4 years ago
An ion of iron has an 26 protons, 30 neutrons, and 23 electrons. What are its atomic number, atomic mass, and net charge?
sleet_krkn [62]

Answer:

Atomic number 26,atomic mass 26+30=56 dalton and net charge is 3+

Explanation:

The total number of proton present in an atom is known as the atomic number of that atom.From that point of view the atomic number of iron ion is 26.

  The total number proton and neutrons present in the nucleus of an atom or ion is termed as atomic mass.From that point of view the the atomic mass of iron ion is 26+30=56 dalton

 According to the given question iron ion contain 3 more protons than electrons as a result the iron ion will contain 3 unit positive charge.

5 0
3 years ago
What is the charge on an electron?
Llana [10]

Answer:

The answer is negative .

3 0
3 years ago
Are there any plans for controlling or removing zebra mussel
Sav [38]

Answer: no

Explanation:

4 0
3 years ago
Other questions:
  • If there are no chemical controls which can be implemented at your worksite, what can you do to protect yourself?
    6·1 answer
  • What occurs in a chemical reaction?
    6·2 answers
  • What is the end result of a nuclear fusion reaction? two new atoms with smaller nuclei form molecule of atoms forms one new atom
    15·2 answers
  • 16. A baseball has a mass of 1500 grams and displaces 500 ml. of water. What is<br> it's density?
    13·1 answer
  • Electric field creates a 3.9 ma current in a 1.0-mm-diameter wire. what material is the wire made of?
    7·2 answers
  • Find the mass in grams of 2.65 x 10^24 molecules of cl2
    10·1 answer
  • Combining 0.380 mol Fe2O3 with excess carbon produced 13.7 g Fe
    14·1 answer
  • En el momento en que sienta que su corazón se hunde y sienta el dolor literal en su pecho ... La peor sensación que he tenido. ¡
    13·1 answer
  • Difference between desirable changes and undesirable changes​
    8·1 answer
  • A gas occupies a 40.0 mL at 50 K. What volume does it occupy at 300K?
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!