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Nata [24]
3 years ago
11

No question here...............

Chemistry
1 answer:
Lady bird [3.3K]3 years ago
4 0

no answer here ......

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Find a mole of 0.0960 g of H2SO4
nignag [31]
Molar mass H₂SO₄ = 98.079 g/mol

1 mol -------- 98.079 g
? mole ------ 0.0960 g

moles = 0.0960 * 1 / 98.079

= 0.0960 / 98.079

= 9.788 x 10⁻⁴ moles

hope this helps!
3 0
4 years ago
What methods were used to clean up the Chernobyl and three mile island accidents?
Assoli18 [71]

<u>Answer</u>:

Electric evaporator has been used to clean up the Chernobyl and 3 mile island accident.

<u>Explanation</u>:

About 14 years back, there was a puff of radioactive steam from the evaporator used in the "Three-mile island" nuclear plant. It took two years for the electric evaporator to clean up the 2.2 million gallons of water that have been destroyed because of the nuclear power plant accident.

The steam that came out of the electric evaporator carried a radioactive form of hydrogen and tritium with itself. Cost of clean up was $1 billion.

6 0
3 years ago
What is the balanced equation for the voltaic cell of copper and silver
Strike441 [17]

Answer:

I dont knw

Explanation:

3 0
3 years ago
I need this ASAP thank you
Rainbow [258]

Answer:

16,,24Mg 17,,a24.1 18a mass number of the most abundant isotope

Explanation:

atomic number of Mg is 12 ,therefore its mass number should be the value that is very close to 24.

24.1 is the value of thee most abundant isotope.

8 0
2 years ago
Arbon dioxide is dissolved in blood (ph 7.5) to form a mixture of carbonic acid and bicarbonate. Part a neglecting free co2, wha
Aleks04 [339]

Answer : The fraction of carbonic acid present in the blood is 5.95%

Explanation :

The mixture consists of carbonic acid ( H₂CO₃) and bicarbonate ion ( HCO₃⁻). This represents a mixture of weak acid and its conjugate which is a buffer.

The pH of a buffer is calculated using Henderson equation which is given below.

pH = pKa + log \frac{[Base]}{[Acid]}

We have been given,

pH = 7.5

pKa of carbonic acid = 6.3

Let us plug in the values in Henderson equation to find the ratio Base/Acid.

7.5 = 6.3 + log \frac{[base]}{[acid]}

1.2 = log \frac{[base]}{[acid]}

\frac{[Base]}{[Acid]} = 10^{1.2}

\frac{[Base]}{[Acid]} = 15.8

[Base] = 15.8 \times [Acid]

The total of mole fraction of acid and base is 1. Therefore we have,

[Acid] + [Base] = 1

But Base = 15.8 x [Acid]. Let us plug in this value in above equation.

[Acid] + 15.8 \times [Acid] = 1

16.8 [Acid] = 1

[Acid] = \frac{1}{16.8}

[Acid] = 0.0595

[Acid] = 0.0595 x 100 = 5.95 %

The fraction of carbonic acid present in the blood is 5.95%

4 0
3 years ago
Read 2 more answers
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