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The given question is incomplete. The complete question is as follows.
A certain liquid has a normal boiling point of and a boiling point elevation constant
. A solution is prepared by dissolving some sodium chloride (NaCl) in 6.50 g of X. This solution boils at
. Calculate the mass of NaCl that was dissolved. Round your answer to significant digits.
Explanation:
As per the colligative property, the elevation in boiling point will be as follows.
T = boiling point of the solution =
= boiling point of the pure solvent =
= elevation of boiling constant =
We will calculate the molality as follows.
molality =
i = vant hoff's factor
As NaCl is soluble in water and dissociates into sodium and chlorine ions so i = 2.
Putting the given values into the above formula as follows.
m = 100 g
Therefore, we can conclude that 100 g of NaCl was dissolved.
