Judging on the question I figured that the perpendicular line's slope would be -x since the slope of a perpendicular line is opposite to that of a the reference line.
Thus, your answer should be y=-x+4 considering that is the only equation with the slope of -x.
We proved that formula using the trigonometry relations sin3A + sinA = 4sinAcos^2A.
In the given question,
We have to prove the formula sin 3A+sin A = 4sinAcos^2A
The given expression is sin 3A+sin A = 4sinAcos^2A
To prove the formula we take the left side terms to the right side terms
The left side is sin 3A+sin A.
As we know that sin 3A = 3sinA − 4sin^3A
To solve the left side we put the value of sin 3A in sin 3A+sin A.
=sin 3A+sin A
=3sinA − 4sin^3A+sin A
Simplifying
= (3sinA+sin A) − 4sin^3A
= 4sinA − 4sin^3A
Taking 4sinA common from both terms
= 4sinA(1 − sin^2A)
As we know that cos^2A=1 − sin^2A. So
= 4sinAcos^2A
We proved the right hand side.
To learn more about formula of trigonometry terms link is here
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7x + 15x + 27 = 247
22x = 247 -27
22x =225
X= 10.22
Answer:
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Step-by-step explanation:
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Answer:
Motor 1) 7 ½ horsepower single phase, 230 volts 40 ampere) ; Motor 2) 5 ... for a 2 horsepower 115 volt motor that has a full-load current rating of 24 ampere, ... Simultaneously disconnects all conductors of the circuit.
