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3 years ago

Why is chlorine bonded by a single covalent bond, but Oxygen bonded by a double covalent bond?

Physics

1 answer:

inna [77]3 years ago

4 0

Answer:

chlorine is a non-metal.

Explanation:

a chlorine atom has 7 electrons in its outer shell. chlorine is in group 7 of the periodic table. two chlorine atoms will each share one electron to get a full outer shell and form a stable cl2 molecule.

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Can some please help me with this?

Lerok [7]

1) Current

2) Atoms

3) Wire

4) Negative

5) Neutron

6) Shock

7) Switch

8) Static

9) Volt

10) Battery

11) Dam

12) Thomas Edison

13) Benjamin Franklin

14) Alessandro Volta

15) Michael Faraday

I would say that these would be your correct answers, btw I'm doing something that is close to the same right now

Hope this helps :)

6 0

2 years ago

A weight lifter lifts a dumbbell a certain height in 2.0 s, while a competitor does the same workin 1.0 s. Compared to the power

Aloiza [94]

Answer:

a. one-half as great

Explanation:

The power developed by the first lifter is one-half as great as that of the second person.

Power is defined as the rate at which work is done;

Power = $\frac{workdone}{time}$

Since the two lifters do the same work at different time, let us estimate their power;

P₁ = $\frac{workdone}{2}$ P₂ = $\frac{workdone }{1}$

We see that for P₁, power is half of the work done whereas in P₂ power is the same as the work done.

Therefore,

The power of the first weight lifter is one-half the second lifter.

4 0

2 years ago

A space station, in the form of a wheel 140 m in diameter, rotates to provide an "artificial gravity" of 3.90 m/s2 for persons w

Zigmanuir [339]

Radial acceleration is given by

$a_{rad}= \frac{v^2}{r}$
where

$v=r \omega$
then

$a_{rad}= \frac{r^2 \omega^2}{r}=r\omega^2$

Now

$70\omega^2=3.90 \frac{m}{s^2} \\ \\ \omega= \sqrt{ \frac{3.9}{70} }$

Using the relation

$\omega=2 \pi f$

$2 \pi f= \sqrt{ \frac{3.9}{70} }\\ \\ f= \frac{1}{2 \pi}\sqrt{ \frac{3.9}{70} }Hz$

Putting into rpm

$\frac{60}{2 \pi}\sqrt{ \frac{3.9}{70}} =2.254rpm$

8 0

3 years ago

PLEASE HELP show the calculation of the number of neutrons of hydrogen

xz_007 [3.2K]

The answer is 2.3 hope this helps texted me and tell me if it’s right

7 0

2 years ago

A 150-W lamp is placed into a 120-V ac outlet. What is the peak current?

devlian [24]

Answer:

Explanation:

Formula

W = I * E

Givens

W = 150

E = 120

I = ?

Solution

150 = I * 120 Divide by 120

150/120 = I

5/4 = I

I = 1.25

Note: This is an edited note. You have to assume that 120 is the RMS voltage in order to go any further. That means that the peak voltage is √2 times the size of 120. The current has the same note applied to it. If the voltage is its rms value, then the current must (assuming the properties of the bulb do not change)

On the other hand, if the voltage is the peak value at 120 then 1.25 will be correct.

However I would go with the other answerer's post and multiply both values by √2

3 0

3 years ago

Read 2 more answers